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Ugo [173]
3 years ago
15

I need help guys! Determine if the following relations represent y as a function of x.

Mathematics
1 answer:
Whitepunk [10]3 years ago
5 0

Functions are relations that only have one output per input (or graphically passes the vertical line test). You can either go on Desmos and graph this or just look at my explanations below.

1) function, pretty much all polynomials will be a normal function

2) function. This is a rational function, meaning you'll have some weird gaps and lines going to infinity but it's still a function. It's formed by a polynomial divided by another polynomial.

3) function, looks like you can simplify this into a standard rational function.

4) relation, y with an even square root are never going to give you a single solution (due to the nature of a + or - answer; \sqrt{9} = +3 and -3)

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What number equals 100 when it is squared
just olya [345]
10 squared equals 100. Another way to say it bcz I need to type more to post the answer is the square root of 100 is 10

7 0
4 years ago
Read 2 more answers
A new post-surgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment, while seven
a_sh-v [17]

Answer:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And repaplacing we got:

\bar X_T = 17.714 the sample mean for treatment

\bar X_C = 28.714 the sample mean for treatment

s_T= 4.461 the sample deviation for treatment

s_C= 7.387 the sample deviation for control

n_T= n_C= 7 the sample size for each sample

The degrees of freedom are given by:

df= 7+7-2= 12

The confidence interval for the difference of means is given by:

(\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}

The confidence is 98% so then the significance is \alpha=0.02 and \alpha/2 =0.01. Then the critical value would be:

t_{\alpha/2}=2.681

And replacing we got:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

4 0
3 years ago
Is 1/8 greater than 1/2?
ololo11 [35]
No, if you find the common denominator of 8, 1/2 will turn into 4/8, which is greater than 1/8. Therefore 1/8 is less than 1/2.
5 0
4 years ago
I need help please help
erastovalidia [21]

Answer:

x = 57*

Step-by-step explanation:

The angles of a triangle add up to 180.

67 + 56 = 123

180 - 123 = 57

57 degrees

6 0
3 years ago
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Marrrta [24]

Answer:

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Step-by-step explanation:

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