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3 years ago

I need HALP PLEASE I MARK BRAINLIEST WHOEVER ANSWER

Mathematics

2 answers:

Tpy6a [65]3 years ago

6 0

Answer:

18ft

Step-by-step explanation:

If every cube is 1/4th foot in volume, then 4 cubes would be equivalent to 1ft. The box we need to measure is 4 cubes high, we can just count how many little cubes are on the top side and the amount of cubes would be at a 1 to 1 with how many square feet in volume the box is.

I'm not confident in this explanation but id be happy to answer questions in comments.

Hope i helped!

Law Incorporation [45]3 years ago

3 0

Answer:

Answer is D

Step-by-step explanation:

Length:

6 x $\frac{1}{4} = 1 \frac{1}{2}$

Width:

3 x $\frac{1}{4}$ = $\frac{3}{4}$

Height:

4 x $\frac{1}{4} = 1$

Now we multiply them all together! For the sake of keeping everything organized, everything will be the same (4ths)

$1\frac{2}{4}$ x $\frac{3}4}$ x $1$ = $1\frac{1}{8}$

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The thing that is true about -5 and 5 is the answer is zero.

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Which of the following statements about the sampling distribution of the sample mean, x-bar, is not true? A. The sampling distri

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Answer: E. All of the above statements are true

Step-by-step explanation:

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3 years ago

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Viktor [21]

Answer:

kitchi kitch ya ya da da

Step-by-step explanation:

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2 years ago

In XYZ, mX=90 and mY=30.In TUV,mU= 30 and mV=60. Which is true about the two triangles? XYZ=TUV, XYZ= VUT,No congruency statemen

Flauer [41]

Answer:

No congruency statement can be made because the side length are unknown.

Step-by-step explanation:

The sum of the measures of all interior angles in a triangle is always 180°.

In triangle XYZ,

$m\angle X=90^{\circ}\\ \\m\angle Y=30^{\circ},$

then

$m\angle X+m\angle Y+m\angle Z=180^{\circ}\Rightarrow m\angle Z=180^{\circ}-90^{\circ}-30^{\circ}=60^{\circ}$

In triangle TUV,

$m\angle U=30^{\circ}\\\\m\angle V=60^{\circ},$

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We have two triangles with congruent angles but we have no information about side lengths. Therefore, can not be made because the side length are unknown. Correct option is last option.

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