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Cloud [144]
3 years ago
8

Point G is located at (3, −1) and point H is located at (−2, 3). Find y value for the point that is the distance from point G to

point H.
2.67
1.67
5.67
0.67
Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0
B. 1.67
m : n = 2 : 1
 ( x, y ) = ( (1*3 + 2*(-2))/(2+1) ;  (1 * (-1) + 2 * 3) /(2 + 1) ) =
 = ( (3-4)/3  ; (-1+6)/3 ) 1.67
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3 0
3 years ago
I dont understand this please help​
Alex787 [66]

Answer:

Its asking you which one is greater or less than. Hope this help?

Step-by-step explanation:

6 0
3 years ago
Find the measure of an angle in a regular polygon with 22 sides​
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8 0
3 years ago
Read 2 more answers
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
-6-5[-4-(6+12)]+(-5)
Luden [163]

Answer:

99

Step-by-step explanation:

-6-5[-4-(6+12)]+(-5)

Following PEMDAS

We work the parentheses from the inside out

-6-5[-4-(18)]+(-5)

-6-5[-22]+(-5)

Now we multiply

-6+110 -5

Now we add and subtract from left to right

104 -5

99

6 0
3 years ago
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