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cluponka [151]
2 years ago
12

6 to 12 please I need help :,)

Mathematics
1 answer:
abruzzese [7]2 years ago
3 0
Samantha read 6 pages in 12 minutes
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The answer would most likely be C
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2 years ago
The metric system is based on multiples of 100. Please select the best answer from the choices provided A.True B.False
Otrada [13]

Answer:

true

Step-by-step explanation:

i think

5 0
3 years ago
Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method
antoniya [11.8K]

Answer:

a

The estimate is  - 0.0265\le  K \le  0.0465

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is  n_1 = 400

The number of faulty breaks of method A is  X_1 = 32

 The number of microchips broken in method B is  n_2  = 400

 The number of faulty breaks of method A is  X_2 = 32

  The proportion of the faulty breaks to the total breaks in method A is

       p_1 = \frac{32}{400}

      p_1 = 0.08

 The proportion of the faulty to the total breaks in method B is

      p_2 =  \frac{28}{400}

     p_2 =  0.07

For this estimation the standard error is  

      SE =  \sqrt{ \frac{p_1 (1 - p_1)}{n_1}  + \frac{p_2 (1- p_2 )}{n_2} } }

  substituting values

       SE =  \sqrt{ \frac{0.08 (1 - 0.08)}{400}  + \frac{0.07 (1- 0.07 )}{400} } }

      SE = 0.0186

The z-values of confidence coefficient of 0.95 from the z-table is  

       z_{0.95} =  1.96

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

        K = [p_1 - p_2 ] \pm z_{0.95} * SE

substituting values

        K = [0.08 - 0.07 ] \pm 1.96 *0.0186

         K  =  - 0.0265 \ or  \ K  =  0.0465

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is  

      - 0.0265\le  K \le  0.0465

3 0
2 years ago
Find the third side in simplest radical form:
larisa [96]

Answer:

x = √53

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

<u>Step 1: Define</u>

We are given a right triangle. We can use PT to solve for the missing length.

<u>Step 2: Identify Variables</u>

Leg <em>a</em> = 6

Leg <em>b</em> = <em>x</em>

Hypotenuse <em>c</em> = √89

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Set up equation:                    6² + x² = (√89)²
  2. Isolate <em>x</em> term:                        x² = (√89)² - 6²
  3. Exponents:                             x² = 89 - 36
  4. Subtract:                                 x² = 53
  5. Isolate <em>x</em>:                                 x = √53
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Suppose you had d dollars in your checking account. You spent $10 but have at least $50 left. How much money did you have initia
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