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expeople1 [14]
2 years ago
14

E

Mathematics
1 answer:
Shtirlitz [24]2 years ago
3 0

Answer:

Point (6, -1) = (x, y)

Slope = -3

The proper linear equation is written in following form: y = mx + b (where m is slope, and b is y-intercept). Since we already have the slope, we need to find the y-intercept, b

So we plug in what we have:

y = mx + b

-1 = (-3)(6) + b, where we solve for b  

-1 = -18 + b  

b = 17

Finally, the equation of the line that passes through point (6, -1) and has a slope of -3 is y = -3x + 17

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