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Vinil7 [7]
3 years ago
15

1. In the following equation a, b, and care constants. In other words, a, b, and c should be

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0
That’s crazy who knew I neeed points rq sorry
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On a coordinate plane, 2 triangles are shown. Triangle A B C has points (negative 1, negative 1), (2, negative 1), and (negative
Juliette [100K]

Triangle RST was reflected over the x-axis and translated 2 units to the left to form triangle ABC. The figures are congruent.

<h3>What is transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>rotation, reflection, translation and dilation.</em>

Reflection, translation and rotation are rigid transformation which preserve the shape and size of a figure, forming congruent figures.

Triangle RST was reflected over the x-axis and translated 2 units to the left to form triangle ABC. The figures are congruent.

Find out more on transformation at: brainly.com/question/4289712

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5 0
2 years ago
Does anyone have course hero (or a math app) where they could ask a few math questions on there for me? It would be a huge help!
jek_recluse [69]

Answer:

There's a website called tiger algebra and it solves any equation you give it with step by step instructions!

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
HILL BOOMERANG I BEG OF YOU GUYS PLEASE HELP IF YOU KNOW AND UNDERSTAND IT
Shtirlitz [24]

Answer:

5. 2√6

6. 4

Step-by-step explanation:

5. x =√[3×(3+5] = √3×8 =√24=2√6

6. x(x+5)=6²

x²+5x=36

x²+5x-36=0

(x+9)(x-4) =0

x=-9 or x=4

4 0
3 years ago
Express 0.7033 as a mixed number
viva [34]
We can make 0.7033 an improper fraction by multiplying it by 10,000 to get:

7033/10,000

Note that this cannot be a mixed number because 10,000, the denominator, is greater than 7033, the numerator. 

You may have misspelled or typoed the question, or the question might be wrong, because 0.7033 can't be written as a mixed number.
7 0
3 years ago
Need some help with indefinite integrals pleasee
goldenfox [79]
Observe that (x^2+2x+2)'=2x+2.

You have that \int \frac{2x}{x^2+2x+2}\; dx=\int \frac{2x+2-2}{x^2+2x+2}\; dx=\int \frac{2x+2}{x^2+2x+2}\; dx+\int \frac{1}{x^2+2x+2}\; dx=I_1+2I_2.

To compute I_1 you set y=x^2+2x+2, so dy=2x+2\; dx. Therefore, I_1=\int \frac{1}{y}\; dy=\ln |y|=\ln |x^2+2x+2|=\ln (x^2+2x+2).

For I_2 observe that x^2+2x+2=(x+1)^2+1. Let y=x+1. Then dy=dx and I_2=\int \frac{1}{y^2+1}=\arctan y=\arctan (x+1).

So, \int \frac{2x}{x^2+2x+2}=\ln (x^2+2x+2)+2\arctan (x+1)+c.
8 0
4 years ago
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