Answer:
Jamie's claims are correct because 3/10 of the spool twine is left over after using 1/2 of the spool twin for friendship knot
Step-by-step explanation:
Full question: He claims to have 3/10 of the original spool of twine leftover.
First, we compare 3/10 with 4/5 - 1/2
The lowest common multiple for2 and 5 is 10.
To write 4/5 as a fraction with common denominator, multiply numerator and denominator by 2
4/5 = (4×2)/(5×2) = 8/10
To write 1/2 as a fraction with a common denominator, multiply denominator and numerator by5
1/2 =(1×5)/(2×5) = 5/0
So we have :
8/10 - 5/10
Since denominators are equal ,we go ahead and subtract
8/10 - 5/10 = (8-5)/10 = 3/10
If it is a square all sides are equal, so the perimeter is equal to 4 times the length of one side...
4s=32
s=8in
Answer:
246.3%
the complete question is found in the attached document
Step-by-step explanation:
1st step:
using 1936 data,
w1= 356% = 3.56(356/100) , H= 79 feet
specific gravity = 2.65
Sₓ= 100%= 1
initial void ratio(e₀)= (w1 x specific gravity)/Sₓ
=3.56 x 2.65/1 = 9.434
2nd step
using 1996 data
ΔH= 22ft
ΔH/H = Δe/(1 + e₀)
22/79 = Δe/(1+9.434)
0.278=Δe/10.434
Δe= 0.278 x 10.434
Δe= 2.905
Δe= e₀ - eₓ
eₓ= e₀-Δe
eₓ= 9.434 - 2.905
eₓ= 6.529
3rd step
calculating water content in 1996
eₓ =6.529, specific gravity= 2.65, Sₓ= 100%
W2 X 2.65 = 1 x 6.529
w2 = 6.529/2.65 = 2.463 = 246.3%
Answer:
4 blocks.
Step-by-step explanation:
