Answer:
2.0
Explanation:
i think 2.0 because u are trying find the magnitude of it
Q: A sport car accelerate at the rate of 2.80m/s². How long does it take to reach its top speed of 60.0 km/h, starting from rest ?
Answer:
5.95 s.
Explanation:
From Newton's equation of motion,
a = (v-u)/t ................ Equation 1
Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time taken to reach the top speed.
Making t the subject of the equation,
t = (v-u)/a.............. Equation 2
Given: a = 2.8 m/s², u = 0 m/s ( from rest), v = 60 km/h = (60×1000)/3600
v = 16.67 m/s.
Substitute into equation 2
t = (16.67-0)/2.8
t = 5.95 s.
Hence the time taken to reach the top speed = 5.95 s.
Answer:
88 m/s
Explanation:
To solve the problem, we can use the following SUVAT equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the distance covered
For the car in this problem, we have
d = 484 m is the stopping distance
v = 0 is the final velocity
is the acceleration
Solving for u, we find the initial velocity:
Answer:
The axis is tilted and points to the North Star no matter where Earth is in its orbit. Because of this, the distribution of the Sun's rays changes. ... It also means that the angle at which sunlight strikes different parts of Earth's surface changes through the year.
Explanation:
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