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3 years ago

7

When light goes through a material but changes direction, the process is called..

1 answer:

Luden [163]3 years ago

6 0

Answer:

<h2><em>This change of direction is called refraction. When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line. The amount of bending depends on two things: Change in speed – if a substance causes the light to speed up or slow down more, it will refract (bend) more.</em></h2><h2><em>Hop</em><em>e</em><em> it</em><em> helps</em><em>.</em><em>.</em></h2>

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If the SAME person does a cannonball from these different heights, which height will produce the biggest SPLASH? WHY?

sveta [45]

Answer:

the impact on the water varies from different heights, therefore the mass stays the same, yet the force on the water increases from a higher height. A taller height will produce a bigger splash!

Explanation:

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3 years ago

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GrogVix [38]

Answer:

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3 years ago

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3 years ago

Read 2 more answers

Find the force between charges of +10.0 C and -50.0 C located 20.0 cm apart

polet [3.4K]

The magnitude of the electrostatic force between the two charges is $1.12\cdot 10^{14} N$

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, we have:

$q_1 = +10.0 C$

$q_2 = -50.0 C$

r = 20.0 cm = 0.20 m

Therefore, the force between the charges is

$F=(8.99\cdot 10^9) \frac{(10)(-50)}{(0.20)^2}=-1.12\cdot 10^{14} N$

where the negative sign means that the force is attractive, since the two charges have opposite sign.

Learn more about electrostatic force here:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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4 years ago

A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that a

Klio2033 [76]

Answer:

$E_{square}=0.51v$

$i_{square}=2.98A$

Explanation:

$E_{mf}=-N*\frac{d\alpha}{dt}$

$E_{mf}=-N*A*\frac{d\beta}{dt}$

$N=1$

$E_{circle}=A_{circle}*\frac{d\beta}{dt}$

$E_{square}=E_{circle}*\frac{A_{square}}{A_{circle}}$

$E_{square}=E_{circle}(\frac{\frac{\pi^2}{4}*r^2}{\pi*r^2})$

$E_{square}=E_{circle}*\frac{\pi}{4}$

$E_{square}=0.65v*\frac{\pi}{4}$

$E_{square}=0.51v$

$i_{square}=i_{circle}*\frac{E_{square}}{E_{circle}}$

$i_{square}=3.8A*\frac{0.51v}{0.65v}$

$i_{square}=2.98A$

8 0

3 years ago