Question

Please Help Please help. See the picture

Answer 1

Answer:

• General equation of a line is as below:

${ \boxed{ \tt{y = mx + c}}}$

→ m is the slope

${ \tt{slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } }}$

• Consider points (0, 3) and (3, 0) from the graph:

${ \tt{slope = \frac{0 - 3}{3 - 0} = \frac{ - 3}{3} }} \\ \\ { \tt{ \underline{ \: \: slope = - 1 \: \: }}}$

→ c is the y-intercept:

• consider point (0, 3):

${ \tt{y = mx + c}} \\ { \tt{3 = ( - 1 \times 0) + c}} \\ { \tt{c = 3}}$

» Therefore, substitute to make the equation of a line:

${ \boxed{ \boxed{ \tt{ \: \: y = - x + 3 \: \: }}}}$