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Murljashka [212]
3 years ago
7

In a histogram, the proportion of the total area which must be to the left of the median is:

Mathematics
1 answer:
Lana71 [14]3 years ago
6 0

Answer:

A. exactly 0.50

Step-by-step explanation:

We have been given a statement. We are asked to choose the correct option about given statement.

We know that every histogram has 5 points summary.

1st point is known as minimum point, 2nd point is first quartile, 3rd point is median, 4th point is upper quartile and 5th point is maximum point.

In a normal distribution 25% of the data points are to the left 1st quartile, 50% of the data points are to the left of median and 75% of the data points are to the left 2nd quartile.

50\%=\frac{50}{100}=0.50

Therefore, exactly 0.50 of the total area which must be to the left of the median.

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(x – 2)^2 + 20 = 0
seraphim [82]

Answer:

x = 2  ± 2 sqrt(5)i

Step-by-step explanation:

(x – 2)^2 + 20 = 0

Subtract 20 from each side

(x – 2)^2 + 20 -20=0 -20

(x – 2)^2 =- 20

Take the square root of each side

sqrt((x – 2)^2) =±sqrt(- 20)

x-2  = ±sqrt(- 20)

We know sqrt(ab) = sqrt(a) sqrt(b)

x-2  = ±sqrt(- 1) sqrt(20)

We know the sqrt (-1) = i

x-2  = ±i sqrt(4*5)

x-2 = ±i sqrt(4) sqrt(5)

Add 2 to each side

x-2+2 = 2 ±i sqrt(4) sqrt(5)

x = 2 ±i 2 sqrt(5)

x = 2  ± 2 sqrt(5)i

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3 years ago
Match each number with its place in order from smallest (1st) to largest (6th).
zheka24 [161]
90 would be the largest then 59,48, -56, -80, and leaving -84 to be the smallest
8 0
2 years ago
What time is 5 3/4 hours after 9:22 pm?
Ronch [10]

Answer:

15:37 or 3:37

Step-by-step explanation:

3/4=0.75

0.75+9.22=9.97

5+9.97=14.97

6 0
2 years ago
Stephen's glass holds 450 milliliters of milk. Farrah's glass holds 2\5 as much milk. How much milk does Farrah's glass holds?
padilas [110]
Farrahs glass holds 180 milliliters of milk.
7 0
3 years ago
Hiro bought a small carton of milk at lunch. If the approximate dimensions of the milk carton are shown what is the minimum amou
faltersainse [42]

Answer:

C.\ 104\ in^2

Step-by-step explanation:

At first, the question looks like an optimization problem, but since all the dimensions of the carton are given, we only have to compute the total area of the given figure.

Let's calculate the front (and back) areas, which are rectangles

A_1=(6.5)(3)=19.5\ in^2

Now with the lateral rectangles which happen to have the very same dimensions

A_2=19.5\ in^2

Next, we compute the front and back triangles of base 3 in and height 1.5 in

A_3=\frac{1}{2}(3)(1.5)=2.25\ in^2

Now, the lateral inclined rectangles of base 3 in and height 2 in

A_4=(3)(2)=6\ in^2

Finally, the base rectangle who happens to be a square of side 3 in

A_5=(3)(3)= 9\ in^2

This last area, unlike all others, is not doubled because its counterpart is inside the carton and is not part of the lateral area

Our total area of cardboard is

A_t=2(19.5)+2(19.5)+2(2.25)+2(6)+9=103.5\ in^2

The closest option to this answer is

C.\ 104\ in^2

5 0
3 years ago
Read 2 more answers
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