You use the definition of median and interquartile range. The def. of a median is the number in the middle of the data set, so the number 6 would be in the middle. Making a box and whisker plot(shown below) with the data set separates the data set into 4 "quartiles" or parts. The interquartile range is the last line in the box(Q3) minus the first line in the box(Q1). So something minus somthing must equal 5.
Data set: 1,2,3,6,8,8,10
It doesn't matter what the other numbers are as long as the median is 6 and the interquartiel range is 6.
The correct option is B.
Thus, 68% percentage of the balls weigh within one standard deviation of the mean.
<h3>What is the empirical formula rule?</h3>
The Empirical Rule indicates that 99.7% of data that are observed to have a normal distribution fall within 3 standard deviations of the mean. According to this formula, 68 percent of the data are within one standard deviation, 95 percent are within two standard deviations, and 99.7 percent are within three standard deviations of the mean.
<h3>According to the empirical formula rule:</h3>
Because approximately 68% of the data falls within a standard deviation of the mean, according to the empirical rule, 68% of the balls' weights fall within that range.
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I understand that the question you are looking for is:
The weights of tennis balls are normally distributed, with the mean being 5.15 ounces and the standard deviation being 0.10. what percentage of the balls weigh within one standard deviation of the mean
A. 50%
B. 68%
C. 95%
D. 99.7%
Answer:
424 cm²
Step-by-step explanation:
The figure is composed of a square and a trapezium on top
A of square = 18² = 324 cm²
A of trapezium = 
h (b₁ + b₂ )
where h is the perpendicular height and b₁, b₂ the parallel bases
Here h = 8, b₁ = 18 and b₂ = 7 , then
A = 0.5 × 8 × (18 + 7) = 4 × 25 = 100 cm²
Area of hexagonal park = 324 + 100 = 424 cm²
