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Vanyuwa [196]
3 years ago
15

A deck is being built around a rectangular swimming pool the swimming pool is 20ft * 12ft and the deck has a uniform width of 6

ft what is the area of the deck only

Mathematics
1 answer:
baherus [9]3 years ago
6 0

The area of the only deck is 528 ft²

<u><em>Explanation</em></u>

The length and width of the swimming pool are 20 ft and 12 ft respectively.

So, <u>the area of the swimming pool</u> =length*width= (20*12)ft^2= 240 ft^2

Now a deck is being built around the pool and it has a uniform width of 6 ft.

So, the length of the pool including the deck =(20+6*2)ft = 32 ft and the width of the pool including the deck =(12+6*2)ft=24 ft

Thus, <u>the area of the pool including the deck</u> =(32*24)ft^2 = 768 ft^2

So, the area of the deck only =(768-240)ft^2 = 528 ft^2

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4 years ago
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harkovskaia [24]
<h3>3 Answers:</h3>

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========================================

Explanation:

Choice A is true because plugging in x = 0 leads to y = 3. Effectively, anything with an x goes away when x = 0 leaving that 3 behind. So finding the y intercept in this form is fairly fast.

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To check choices B through D, let's convert the equation into vertex form.

y = -1x^2 - 2x + 3 is in the form y = ax^2 + bx + c where

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Plug the values of 'a' and 'b' into the equation below

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The y coordinate of the vertex is 4, meaning k = 4

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