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3 years ago

8

Maxim/Minimum Extrema derivatives

1 answer:

erastova [34]3 years ago

8 0

so every time the phrase 'minimum' or 'maximum' show up in a problem with an equation, it means we need to do the math operation of taking the derivative. make senes?can you find the derivative of the equation given?

4.1billion barrels in 2005

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Please help and show work

mylen [45]

7.B
$\sqrt{\pi } = 1.772$
$\pi = 3.142$
$2 \times \pi = 6.283$
${\pi}^{2} = 9.869$

9.A
3/2=1.5

8. F
2times pi =6.283
square root of 50= 7.071
pi squared/2= 3.289

10.H
1/7= .143
which means it can't be f or g.

8 0

3 years ago

The sum of three integers is 228. The second integer is 1 more than the first, and the third integer is 2 more than the first. W

MaRussiya [10]

Ok so to start, your unknown numbers will ne represented as x. The equation looks like this: x+x+1+x+2=228. You have your unknown number, the number plus one, and the numner plus two. To find the answer you divide 228 by 3. Those numbers are all equal though,so you play around with them until you get 75+75+1+75+2=228

7 0

3 years ago

A maritime flag is shown. What is the area of the shaded part of the flag? Explain

Rom4ik [11]

Answer:

<em></em> $Area = 72in^2$ <em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate the Area:</em>

<em></em> $Area_1 = Length * Width$ <em></em>

<em></em> $Area_2 = 8in * (6in + 6in)$ <em></em>

<em></em> $Area_2 = 8in * 12in$ <em></em>

<em></em> $Area_1 = 96in^2$ <em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em> $Area_2 = \frac{1}{2} * base * height$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * (6in + 6in) * 4in$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * 12in * 4in$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * 48in^2$ <em></em>

<em></em> $Area_2 = 24in^2$ <em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em> $Area = Area_1 - Area_2$ <em></em>

<em></em> $Area = 96in^2 - 24in^2$ <em></em>

<em></em> $Area = 72in^2$ <em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0

2 years ago

Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

$k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0$

$k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0$

$3\cdot k^{3} - 3\cdot k - 1 = 0$

7 0

3 years ago

Express 2log 4 + 3log 2 as a single logarithm

jeka94

Answer:

Step-by-step explanation:

WHEN ADDING TWO LOGS TO COMPRESS THEM YOU MULTIPLY THE TERMS

LOG(4^2)(2^3)

LOG(16)(8)

LOG(128)

3 0

3 years ago