For x, (52tan)/1=x/35=44.79 which simplifies to 44.80
For y, (52sin)/1=44.80/x=56.852 which simplifies to 56.85
For z, sin^-1=(35/56.85)=37.9995 which simplifies to 38.00.

7 0

2 years ago

in the drawing six out of every 10 tickets are winning tickets of the winning tickets one out of every three awards is a larger

Dafna11 [192]

$Answer: P(\text{a ticket is randomly chosen will award a large prize)}=\frac{2}{21}$

Since we have given that

Total number of tickets =10

Number of winning tickets =6

$\text {Possibility of getting a winning ticket }=^{10}C_6$

In which one out of every three awards is a large prize

so,

$\text{ Possibility of getting a large prize }=^6C_3$

Now,

$P(\text{a ticket is randomly chosen will award a large prize)}=\frac{^6C_3}{^{10}C_6}\\\\=\frac{20}{210}\\\\=\frac{2}{21}$

$P(\text{a ticket is randomly chosen will award a large prize)}=\frac{2}{21}$

8 0

4 years ago

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