There is a typo error in the last part of the question. The corrected part is-
"If the probability that she orders just a grilled cheese sandwich is .76, what is the probability that she will order a grilled cheese or fries?"
Answer:
The probability that she will order a grilled cheese sandwich or fries is <u>0.43.</u>
Step-by-step explanation:
Given:
Probability of ordering fries is, 
Probability of ordering cheese sandwich is, 
Probability of ordering both sandwich and fries is, 
Probability of ordering cheese sandwich or fries is given by the union of both the events 'F' and 'S' given as
.
Now, using addition theorem of probability, we get:

Therefore, probability of ordering cheese sandwich or fries is 0.43.
Answer:
there in not enough information in your question to get an answer
Answer: $2 or $9
<u>Step-by-step explanation:</u>
Revenue (R) = $1800 , x = 1100 - 100p
R = xp
1800 = (1100 - 100p)p <em>substituted x with 1100 - 100p</em>
1800 = 1100p - 100p² <em>distributed p into 1100 - 100p</em>
100p² - 1100p + 1800 = 0 <em>added 100p² & subtracted 1100p</em> on both sides
p² - 11p + 18 = 0 <em>divided both sides by 100</em>
(p - 2) (p - 9) = 0 <em>factored quadratic equation</em>
p = 2 p = 9 <em>applied Zero Product Property to solve for p</em>
<em />
Answer:
Step-by-step explanation:
-13 = 5(1+4m)-2m
-13=5+20m-2m
-13=5+18m
-13-5=18m
(-13-5)/18=m
I = p * r * t
264 = p * .06 * 2
264 = .12p
Divide both sides by .12
p = $2200