Answer:
Explanation:
The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter a number of type double to calculate square root:");
double num = in.nextDouble();
rootPositive(num);
}
public static void rootPositive(double num) {
if (num > 0) {
System.out.println(Math.sqrt(num));
} else {
System.out.println("Number must not be negative.");
}
}
}
A device that sucks bc mien broke
```
#!/usr/local/bin/python3
foo = float( input( "Enter a number: " ) )
if( foo < 0.0 ):
print( "negative" )
elif( foo > 0.0 ):
print( "positive" )
else
print( "zero" )
exit( 0 )
```
Answer:
true because I just had a test like this today and it put true and got it correct