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3 years ago

The temperature in Yarmouth is 6.5 C. In Sydney it is 8C colder. What is the

Mathematics

1 answer:

lukranit [14]3 years ago

4 0

If Yarmouth is 6.5C and Sydney is 8C colder you would just subtract.
6.5-8=-1.5C

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3 years ago

Weights of female cats of a certain breed are normally distributed with mean 4.1 kg and standard deviation 0.6 kg.

Diano4ka-milaya [45]

The proportion is 0.4401.

We find z-scores that correspond with both ends of this interval. Z-scores are given using the formula:

$z=\frac{X-\mu}{\sigma}$

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3 years ago

HELP FASTTTT

UkoKoshka [18]

The line plot illustrates the capacity of the kitchen sink in gallons, and it has a sample size is 21. The distribution is positively skewed, with an appropriate measure of center is 16 and an appropriate measure of spread is 2.5

<h3>The description of the data</h3>

The dataset on the line plot represents the capacity of the kitchen sink.

The capacities are measured in gallons

<h3>The number of data values</h3>

This is the number of dots on the line plot.

There are 21 dots on the plot

Hence, the number of data values is 21

<h3>The shape of the distribution</h3>

The shape of the given distribution is positively skewed.

This is so because there are more points on the left of the distribution

<h3>Appropriate measure of center</h3>

The median is the appropriate measure of center for a skewed distribution.

So, we simply calculate the median.

The median position is calculated using

Median = 0.5 * (n + 1) th

So, we have:

Median = 0.5 * (21 + 1) th

Median = 11th

The 11th data element is 16

Hence, the value of an appropriate measure of center is 16

<h3>Appropriate measure of spread</h3>

The IQR is the appropriate measure of spread for a skewed distribution.

The IQR is:

IQR = Q3 – Q1

Where:

Q3 = 0.75(n + 1)th and Q1 = 0.25(n + 1)th

This gives

Q3 = 0.75 * (21 + 1)th = 16.5

Q1 = 0.25(21 + 1)th = 5.5

The 16.5th element is 17.5, while the 5.5th element is 15

Recall that:

IQR = Q3 – Q1

So, we have:

IQR = 17.5 - 15

Evaluate

IQR = 2.5

Hence, the value of an appropriate measure of spread is 2.5