Hack
for y=ax^2+bx+c
the xvalue of the vertex is -b/2a
and the y value is found by subsituting that for x
so
-b/2a
h(t)=2x^2+4x+7
a=2
b=4
-b/2a=-4/(2*2)=-4/4=-1
the y value
h(-1)=2(-1)^2+4(-1)+7
h(-1)=2(1)-4+7
h(1)=2+3
h(1)=5
(-1,5) is da vertex
Answer:
3
Step-by-step explanation:
Sorry hope you find the answer that you’re looking for I am not much help
Answer:
You didn't say which two answers to choose from but they could possibly be 5^-4, (1/5)^4
Step-by-step explanation:
