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katovenus [111]
3 years ago
6

Help pleaseeeeeeeee :)

Mathematics
2 answers:
Alchen [17]3 years ago
7 0

\Large\leadsto \sf \frac{1}{2} (x \:  +  \: 9) \:  =  \: 3

\Large\leadsto\sf\frac{1}{2} x \:  +  \:  \frac{9}{2}  \:  =  \: 3

\Large\leadsto\sf \frac{2x \:  +\: 18}{4}  \:  =  \: 3

\large \leadsto\sf 2x \:  +  \: 18 \:  =  \: 3 \:  \times  \: 4

\large\leadsto\sf2x +  \: 18 \:  =  \: 12

\large\leadsto\sf2x \:  = 12 \:  -  \: 18

\large\leadsto \sf 2x \:  =  \: -  6

\Large\leadsto\sf \: x \:  =  \:  \cancel\frac { - 6}{2}

\large\leadsto\sf  \pmb{ \: x \:  =  \:  - 3}

nexus9112 [7]3 years ago
5 0

Answer:

x=-3

Step-by-step explanation:

x+9 = 3.2=6

x= 6-9=-3

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An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

10C7=\frac{10!}{7!(10-7)!}=120

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0
3 years ago
There are 50 pennies in a roll. If you have 150 rolls of pennies, how many pennies do you have?
Y_Kistochka [10]

Answer: 7500

Step-by-step explanation:

multiply 150 by 50

8 0
2 years ago
You can buy 2 tickets to school carnival for $9 total.<br> How many tickets can you buy for $27?
kodGreya [7K]

Answer:

6

Step-by-step explanation:

pls brainliest

9/2=4.5

27/4.5=6

3 0
3 years ago
Need help with 56 plz!
Naddika [18.5K]

Answer: No idea, sorry. I'm sure you could look it up tho


Step-by-step explanation:


3 0
3 years ago
I need help quick please help me thnak you
quester [9]

Answer:

28 numbers

Step-by-step explanation:

There is a distance of 81 between -0.5 and 80.5. Divide this number by 3, since you are only counting every third number and you will get 27, but you need to count the first number, which has been excluded. Add one more to get the answer, 28.

3 0
3 years ago
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