
is a quadratic function, so its graph is a parabola.
Notice that the coefficient of x is 0, this always means that the axis of symmetry is the y-axis.
That is, the vertex of the parabola is in the y-axis, so the x-coordinate of the vertex is 0.
for x=0, y=-1. So the vertex is (0, -1)
The coefficient of

is negative. This means that the parabola opens downwards, so the vertex is a maximum.
Answer: (0, -1) , maximum (none of the choices)
The true statement is (c) No; the slopes of segment EF and segment DF are not opposite reciprocals.
<h3>
Right triangles </h3>
Right triangles have a pair of perpendicular lines
Coordinates
The coordinates are given as:
- D = (-2,-1)
- E = (-2,2)
- F = (0,0)
<h3>Slopes</h3>
Start by calculating the slopes of lines DF and EF using:

So, we have:


Also, we have:



For the triangle to be a right triangle, then the calculated slopes must be opposite reciprocals.
i.e.

By comparison, the slopes of both lines are not opposite reciprocals.
Hence, the true statement is (c)
Read more about right triangles at:
brainly.com/question/17972372
Distribute
y+10+c=z
minus y from both sides
10+c=z-y
minus 10 both sides
c=z-y-10
Answer: c
Step-by-step explanation:
Because group B has Pharrell lines