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3 years ago

PLS HELP ME I NEED THIS PLS

Mathematics

2 answers:

melomori [17]3 years ago

5 0

24 with a remainder of 3

liubo4ka [24]3 years ago

4 0

Answer:

24 remainder 3.

Step-by-step explanation

Hope this helps!

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At 11 hours, 42 minutes and 5 hours, 46 minutes

butalik [34]

Answer

https://zoom.us/j/99385592884?pwd=ajVOcXZSbGcyT3N3N0kxQm5Zek81Zz09er:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Surface area of a right cone. <br>Solve for P S=2b+ph

Leya [2.2K]

S = 2b + ph

Lets subtract both sides by 2b

s - 2b = ph

Now, divide both sides by h

(s-2b)/h = p

Hope this helps!

7 0

4 years ago

2x-y=-1 , 3x-y=2 solve by substition

Mazyrski [523]

Answer:

x = 3, y = 7

or (3,7)

Step-by-step explanation:

We are given the system of equations below:

$\large{ \begin{cases} 2x - y = - 1 \\ 3x - y = 2 \end{cases}}$

We are required to solve the system by substitution method. What we have to do is to isolate either x-term or y-term so we can use the method. I will be isolating y-term because it is faster due to having 1 as a coefficient.

By isolating y-term, just pick one of the given equations to isolate. No need to isolate the whole system. (I will be isolating y-term of the first equation.)

$\large{ \begin{cases} y= 2x + 1\\ 3x - y = 2 \end{cases}}$

Then we substitute y = 2x+1 in the second equation.

$\large{3x - (2x + 1) = 2}$

Use the distribution property.

$\large{3x - 2x - 1 = 2}$

Isolate x-term to solve the equation.

$\large{x = 2 + 1} \\ \large{x = 3}$

Since we are solving a system of equations. We have to solve for both x-value and y-value to complete. We have already found x-value, but nor y-value yet. Therefore, our next step is to substitute the value of x that we solved in any given equations. It's recommended to substitute in an equation that doesn't have high coefficient value. So I will be substituting x = 3 in the first equation.

$\large{2x - y = - 1} \\ \large{2(3) - y = - 1} \\ \large{6 - y = - 1}$

Isolate and solve for y-term.

$\large{6 + 1 = y} \\ \large{7 = y} \\ \large{y = 7}$

Since we substitute x = 3 and get y = 7. We can write in ordered pairs as (3,7)

Hence, the solution is (3,7)

7 0

3 years ago

Math question: Write the equation of the line with an undefined slope, passing through the point (2, 5).

lana [24]

When an equation has a line with an undefined slope, it means that the line is vertical.

(2,5); 2 is the x - coordinate and 5 is the y - coordinate

Slope - intercept form: y = mx + b

As shown above, the equation would've been written in slope - intercept form, where 'm' represents the slope and 'b' represents the y - intercept. However, in this case, the slope is undefined.
In the equation, you are ONLY looking for the x - intercept. Therefore, the x - intercept is 5, so that may be the equation of the line.

x = 5

4 0

3 years ago

Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a

NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

$P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

And then substitute the values in it then

$Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

Learn more about probability here

brainly.com/question/24756209

#SPJ4

7 0

2 years ago