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ra1l [238]
3 years ago
6

I dont get adding and subtracting negative & positive numbers.

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
6 0

Answer:

One way to help remember is to visualize it on a number line.

<em>-2</em> is<em> 2 less then 0.</em>

<em>4 </em>is <em>4 more then 0</em>

So, in the equation 4 + (-2), you start at <em>4</em> then go <u>left</u> on a number line <u>twice</u>.

4+(-2) = 2

The same goes for -2 + 4, start at <em>-2 </em>on a number line and go <u>right</u> 4 times.

-2+4 = 2

Simply, with negative numbers you go left and with positive you go right.

-16 + (-16) = -32

52+(-34)=18

When you see [number]+(-[number]), all that means is a positive number plus a negative number, which means a positive number minus the number that is negative as a positive. If that sounds confusing it's alright.

If you need more explanation, you can ask me in the replies

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Need help and if you helped thanks
Marysya12 [62]

Answer:

132

Step-by-step explanation:

36/(6+10)(66)

36/16(66)

2(66)

132

3 0
4 years ago
Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

So

\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}
8 0
3 years ago
What is the solution to the system of equations
Scrat [10]
C (3,1)

There is the answer and also a check to make sure hope this helps

6 0
3 years ago
11. The doubling time of a population of plants is 12 years. Assuming that the initial population is 300 and that the rate of in
Anastasy [175]

Answer:

The population will be of 2400 in 36 years.

Step-by-step explanation:

The equation for the population of plants after t years follows the following format:

P(t) = P(0)(1+r)^{t}

In which P(0) is the initial amount of plants and r is the yearly rate which it increases.

Assuming that the initial population is 300

This means that P(0) = 300.

The doubling time of a population of plants is 12 years.

This means that P(12) = 2*300 = 600.

We use this to find r.

P(t) = P(0)(1+r)^{t}

600 = 300(1+r)^{t}

(1+r)^{12} = 2

\sqrt[12]{(1+r)^{12})} = \sqrt[12]{2}

1 + r = 1.05946

So

P(t) = 300(1.05946)^{t}

How large will the population be in 36 years

This is P(36)

P(t) = 300(1.05946)^{36} = 2400

The population will be of 2400 in 36 years.

6 0
3 years ago
Write an expression to represent: One more than the quotient of a number x and 4.
r-ruslan [8.4K]
1+(X/4) I believe is the answer
4 0
4 years ago
Read 2 more answers
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