Answer:
The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

93% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
<span>2x + 5 =8x
6x = 5
x = 5/6
12x = 12(5/6) = 10</span>
Answer:
1.5 batches take 12.375 hour
Step-by-step explanation:
The first batch takes 10.5 hours, meaning only .5 batches are left. You then take the time that each new full batch takes (4.25) and divide it by 2 as you only need half of one batch. Meaning 0.5 of a batch takes 2.125 hours. You then take the time of the two batches (10.5, and 2.125) and add them, leaving you with 12.625. Meaning 12.375 is the most viable answer.
Answer:
1. x^4 -x^3 -4x^2 -3
a1 = -7.4
an = an-1 -13.8 (choice 1)
Step-by-step explanation:
f(x) = x^4 -x^2 +9
g(x) = x^3 +3x^2 +12
We are subtracting
f(x) -g(x) =x^4 -x^2 +9 - ( x^3 +3x^2 +12)
Distribute the minus sign
x^4 -x^2 +9 - x^3 -3x^2 -12
I like to line them up vertically
x^4 -x^2 +9
- x^3 -3x^2 -12
-------------------------
x^4 -x^3 -4x^2 -3
2. a1 = -7.4
To find the common difference, take term 2 and subtract term 1
-21.2 - (-7.4)
-21.2 + 7.4
-13.8
an = an-1 -13.8
We are trying to represent the change in position of a bird flying down 7 ft to the ground.
Often, for the y axis- up is positive and down is negative.
Change in position is displacement- how far it was from the starting point
( different from distance which is how far is traveled
ex. doubling back would have distance they traveled some distance while the displacement is 0 because they are back to where they started).
The bird is going down 7 ft from where it originally was, which can be represented by
Bird's displacement = -7 ft