All categories

4 years ago

Write a word problem for the absolute value

1 answer:

7 0

If you are at sea level and diving and you descend 500 ft, then how far are you away from sea level?
0+|-500|=500 feet away from sea level

You might be interested in

The distribution of SAT scores of all college-bound seniors taking the SAT in 2014 was approximately normal with a mean of 14971

RideAnS [48]

Answer:

P(X<1200) is 0.8212

Step-by-step explanation:

Test statistic (z) = (X - mean)/sd

X is score of a tester = 1200

mean = 1497

sd = 322

z = (1200 - 1497)/322 = -297/322 = -0.92

The cumulative area of the test statistic is the probability that X<1200. The cumulative area is 0.8212.

Therefore, P(X<1200) = 0.8212

8 0

3 years ago

Read 2 more answers

Please help me!

dybincka [34]

Answer:

They are only equal on day 0, both having 10 population.

Step-by-step explanation:

Given the bacteria on the counter is initially measured at 5 and doubles every 3 days we can generate the following geometric equation:

$f(x)=10*2^{\frac{x}{3} }$

Given the bacteria on the stove is measured at 10 and doubles every 4 days we can create another equation:

$f(x)=10*2^{\frac{x}{4} }$

To find how many days it will take for the bacteria population to equal the same lets set both equations equal to eachother:

$10*2^{x/3}=10*2^{x/4}$

Divide both sides by 10

$2^{x/3}=2^{x/4}$

Since both exponents have the same base we can set the exponents equal to eachother and solve for x:

$\frac{x}{3}=\frac{x}{4}$

Multiply both sides by 3 to isolate x on the left side

$x=\frac{3x}{4}$

Multiply both sides by 4 to remove fraction

$4x=3x$

Subtract 3x to isolate x on the left side

$x=0$

Plug x into one of our original equations

$f(0)=10*2^{0/3}$

Solve

$f(0)=10$

6 0

2 years ago

Solve: k /8 + 1 − = −19

Sonja [21]

Answer:

k = -144

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A hypothesis will be used to test that a population mean equals 10 against the alternative that the population mean is more than

PilotLPTM [1.2K]

Answer:

A) 2.58

B) 1.96

C) 1.65

Step-by-step explanation:

A hypothesis used to test that

$H_o : \mu = 10$

against the alternatives $H1 : \mu$ not equal to 10

if null hypothesis is true, then distribution of test statics follow

$Zo = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}$

for two sided alternatives hypothesis $( H1: \mu \neq 7)$ , then P value is

$P = 2[1- \phi(\left | Zc \right |)]$ (1)

a)significance level $\alpha = 0.01$

from 1 eq we get

$\pi (\left | Zc \right |) = P(Zo$

Therefore $\left | Zc \right | = 2.58$ FROM Z TABLE

B) significance level $\alpha = 0.05$

from 1st equation we get

$\pi (\left | Zc \right |) = P(Zo < \left | Zc \right |) = 1 - \frac{0.05}{2} = 0.975$

Therefore $\left | Zc \right | = 1.96$ FROM Z TABLE

C) significance level $\alpha = 0.10$

from 1 eq we get

$\pi (\left | Zc \right |) = P(Zo$

Therefore $\left | Zc \right | = 1.65$ FROM Z TABLE

3 0

4 years ago

What expression is equivalent to (8 squarded )and -4

kiruha [24]

Answer:

$8^{2} + -4$ = 64 - 4 =60

Step-by-step explanation:

5 0

3 years ago