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3 years ago

0.135 written as a fraction

Mathematics

2 answers:

OleMash [197]3 years ago

8 0

Answer:

135/1000

27/200

Step-by-step explanation:

nadezda [96]3 years ago

8 0

Answer:

Steps to convert decimal into fraction

Write 0.135 as

0.135

Multiply both numerator and denominator by 10 for every number after the decimal point

0.135 × 1000

1 × 1000

135/1000

Reducing the fraction gives

27/200

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3 years ago

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The width of the rectangle is 75% of its length. The length is 8 cm. What is the width of the rectangle?

hjlf

Given :

The length of the rectangle, l = 8 cm/

The width of the rectangle, w = 75% of 8 cm

$= \frac{75}{100} \times 8$

$=\frac{15}{20} \times 8$

= 0.75 x 8

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Therefore, the width of the rectangle is 6 cm.

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3 years ago

Find the 5th term of the geometric progression of the following values 1,2,4 and 8

creativ13 [48]

Answer:

Hello,

Step-by-step explanation:

$2^{0} = 1$

$2^{1} = 2$

$2^{2} = 4$

$2^{3} = 8$

$2^{4} = 16$

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2 x 8 = 16

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Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc

Tamiku [17]

Answer:

$0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697$

$0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903$

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: