Without more information, I assume it's a square and it's w/l =6.5 cm
7/10 of the degrees of a circle is 252 . I dont know the second part of the question sorry.
Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
Answer:
POW
Step-by-step explanation:
Answer:
To find the area of a square with only the diagonal known,
Square the diagonal and divide by 2:
8^2 = 64
64/2 = 32
The area is 32 cm^2
