Answer:
The amount present in a sample of 401 grams after 25 years is
Step-by-step explanation:
we have
A(t) -----> the amount, in grams, of polonium 210 present in a given sample
t -----> the time in years

we know that
To find out the amount present in a sample of 401 grams after 25 years, substitute the value of t=25 years in the equation and solve for A(t)
For t=25 years
Answer:
7+√5/4
Step-by-step explanation:
if that is = a, find the value of a + 1 over a
Given that a = 3 - √5
a+1/1 = (3-√5)+1/3 - √5
4-√5/3 - √5
Rationalize
4-√5/3 - √5 * 3+√5/3 + √5
= 12 +4√5-3√5-√25/9-5
= 12+√5-5/4
= 7+√5/4
Hence the requred answer is 7+√5/4
Answer:
21 stations
Step-by-step explanation:
1 1/4 = 5/4
26.2 / 5/4 = 20.96
rounded up to 21
True, you can see that there is no negative in the problem, also by graphing you can tell that it is increasing