Answer:
(6,-6)
Step-by-step explanation:
if I am correct then give me brainiest
(goh)(x) = (g(x))(h(x)) = (x^2)(x-7) = x^3 -7x^2
then (goh)(5) = (5^3)-7(5)^2 = 124-7(25) = 124-175 = -51
Step-by-step explanation:
this creates a right-angled triangle.
the right angle (90°) being the angle between flag pole and ground.
the angle ground-wire is 50°.
because we know that the sum of all angles in a triangle is always 180°, we know then that the angle flagpole-wire is
180 - 90 - 50 = 40°
so, we have the situation to know 1 side and all angles.
to get the other sides we use best the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
where the sides and related angles are always opposite of each other.
in our case now we have
24/sin(50) = wire/sin(90) = wire/1 = wire = 31.32977494... ft
so, the rounded answer is that the wire must be
31.3 ft long
C = sin⁻¹ (sin(B) * c / b) = sin⁻¹ (sin [90degrees] * 6 / 12.00) = 30 degrees
Answer:
AB , AD , EF , EH all intersect AE ⇒ answer (c)
Step-by-step explanation:
∵ AE segment passing through A and E
∴ Each segment passing through A and E intersects AE
∴ AB intersects AE at A
∴ AD intersects AE at A
∴ EF intersects AE at E
∴ EH intersects AE at E
∴ The answer is (c)
Step-by-step explanation:
