Answer:
C
Step-by-step explanation:
tanA =
=
=
=
→ C
We are technically FOILing this out... with a power of 3.
(x+y)(x+y)(x+y)
So we can first factor out the first two "x+y"s.

, multiplied by the last "x+y".

Coefficients are the number that comes
in front of a variable. In this case, 1 comes in front of

, 3 comes in front of

, 3 comes in front of

, and 1 comes in front of

.
Thus: 1, 3, 3, 1.
Answer Choice A
113 is one number. 131 is another
137, 173
I think that's all of them.
You can check if you google 'list of primes'.
Hold on i'm not sure about 113 and 131 Is number 1 a prime number? I dont think it is , So that leaves us with only 137 and 173.
Answer: y = 10x+14 (choice A)
===================================
Work Shown:
y = 7(x+2)+3x
y = 7x+7*2+3x ..... distribute
y = 7x+14+3x
y = (7x+3x)+14
y = 10x+14
This is in y = mx+b form with m = 10 as the slope and b = 14 as the y intercept.
Answer:
The possible combinations of two letters is 12
Step-by-step explanation:
Here, we want to count the possible combinations of two letters
Now, for the first letter any point in time, we have 4 letters to pick from,
For the second letter we have 3 letters to pick from
So therefore, we have the possible combinations as;
4 * 3 = 12