I think the answer may be that an event is as likely as not to happen when the probability of the event happening is 50%, and the probability of the event not happening is 50%. Like a coin toss, the chance you will flip a "heads" is 1/2 or 50%, and the chance that you WON'T flip a heads is also 1/2 or 50%
The answer is
![r= \sqrt[3]{GMT^{2}/4 \pi^{2}}](https://tex.z-dn.net/?f=r%3D%20%5Csqrt%5B3%5D%7BGMT%5E%7B2%7D%2F4%20%5Cpi%5E%7B2%7D%7D%20)
Move
to the other side of the equation:
Rearrange:
Since
![x^{3}= \sqrt[3]{x}](https://tex.z-dn.net/?f=%20x%5E%7B3%7D%3D%20%5Csqrt%5B3%5D%7Bx%7D%20%20)
, then
![r^{3} = GMT^{2}/4 \pi^{2} \\ r= \sqrt[3]{GMT^{2}/4 \pi^{2}}](https://tex.z-dn.net/?f=r%5E%7B3%7D%20%3D%20GMT%5E%7B2%7D%2F4%20%5Cpi%5E%7B2%7D%20%5C%5C%20%0Ar%3D%20%5Csqrt%5B3%5D%7BGMT%5E%7B2%7D%2F4%20%5Cpi%5E%7B2%7D%7D%20)
Im not sure what you need answer.. Mind if you specify ?
I think what you meant was
(2x - 5)² = 11 -- (1)
Square root both sides of (1), i.e.
√(2x - 5)² = ± √11 -- (2)
From (2), we have
2x - 5 = ± √11 -- (3)
By adding 5 to both sides in (3), we have
2x = 5 ± √11 -- (4)
Divide both sides of (4) by 2, and we obtain
x = (5 ± √11)/2 -- (5)
From (5), the solution set of (1) is
x = (5 + √11)/2, (5 - √11)/2 ...Ans.
