Answer:
Options A) and E)
Step-by-step explanation:
If you use Ruffini's method for polynomials, you can find the roots.
The given picture shows us the first root of the polynomial 
wich is 2.
Thus, the original polynomial can be written as
Here, you can notice that (x-2) is a factor
You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
Answer:
ok im not sure this is the right answer to your specific question, because i dont understand the wording to well, but here...
for 1/7 and 1/2 it would be 2/7 and 1 (whole)
for 1 and 1/7 it would be 2(whole) and 2/7
for 1 and 2/7 it would be 2(whole) and 4/7
for 4/9 it would be 8/9 and x
and for 2/9 it would be 4/9 and x
sorry if thats not the question :)
EDIT: its the second one because
2*1/7= 2/7
and 1/2*2=1
3^2 + 4^2 = 5^2
9 + 16 = 25
25 = 25
5^2 + 12^2 = 13^2
25 + 144 = 169
169 = 169
9^2 + 12^2 = 15^2
81 + 144 = 225
225 = 225
<span>a^2 + b^2 is = to c^2</span>
