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dimulka [17.4K]
3 years ago
5

Solve the following system of equations:

Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0

Answer:

(1, 3) is the answer! hope this helps

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Evaluate 0.53n+5 when n=3 and when n=-3
melomori [17]
<span>0.53(3)+5 = 1.59 + 5 = 6.59 when n = 3
</span>0.53(-3)+5 = -1.59 + 5 = 3.41 when n = -3
4 0
3 years ago
Read 2 more answers
Your test scores for the semester are 87,84 and 85.Can you raise your test average to 90 with you next test?
Rainbow [258]

Answer:

Yes

Step-by-step explanation:

If you add 87.84, 85, and 100 you get 272.84. Once you divide that by 3 you get 90.946, which would be your test average if you score 100 on your next test.

6 0
3 years ago
Do these two have the correct answers?
Lapatulllka [165]
Yes, both of your answers are correct.

Since Death Valley is below sea level, the hiker increases altitude before stopping at 0 feet.

Percent of increase is given by the formula (amount of change)/(original amount) * 100.  Your work is accurate.
7 0
3 years ago
Write as a product: 25a2−0.01b10
Yakvenalex [24]

Answer:

We conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

Step-by-step explanation:

Given the expression

25a^2-0.01b^{10}

Rewrite 25a^2-0.01b^{10} as \left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

so

25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

Apply difference of two squares formulas:

x^2-y^2=\left(x+y\right)\left(x-y\right)

so

\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)

                               =\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)    ∵ \sqrt{0.01}=0.1,

Therefore, we conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

7 0
3 years ago
PLS SAY WHY ITS THE ANSWER YOU CHOSE PLEASEEEE!!!!!! If the diameter of a cylinder is 14 feet and its height is 4 feet, the volu
skelet666 [1.2K]

Answer:

False

Step-by-step explanation:

V = 3.14 x r^2 h = 3.14 x 7^2 x 4 = 615.75216

8 0
3 years ago
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