Given:
95% confidence level
sample size (n) = 91
Find: the lower and upper critical values in a chi-square distribution
Solution:
1. Calculate the degrees of freedom. Since the number of rows and columns is not specified in the question, we will subtract 1 from the sample size.
Our degrees of freedom (df) = 90.
2. Since this is two-tailed, subtract 0.95 from 1, then divide the result by 2.
3. Let's now look at the chi-square distribution table and look for df = 90 with a probability of 0.025 on both the left and right tails.
Based on the table, the lower critical value is 65.647 while the upper critical value is 118.136.
Hence, the answer is Option B.
Answer:
x= -5/3 y-5
Step-by-step explanation:
3^2 + height^2 = 9^2
9 + height^2 = 81
height ^2 = 72
height = sqrt(72)
Third term = t3 = ar^2 = 444 eq. (1)
Seventh term = t7 = ar^6 = 7104 eq. (2)
By solving (1) and (2) we get,
ar^2 = 444
=> a = 444 / r^2 eq. (3)
And ar^6 = 7104
(444/r^2)r^6 = 7104
444 r^4 = 7104
r^4 = 7104/444
= 16
r2 = 4
r = 2
Substitute r value in (3)
a = 444 / r^2
= 444 / 2^2
= 444 / 4
= 111
Therefore a = 111 and r = 2
Therefore t6 = ar^5
= 111(2)^5
= 111(32)
= 3552.
<span>Therefore the 6th term in the geometric series is 3552.</span>
Answer:
9 inches
Step-by-step explanation:
A circle has a diameter of 18 inches
The radius of the circle can be calculated as follows
Radius= diameter/2
= 18/2
= 9 inches
Hence the radius of the circle is 9 inches