Answer:
= 1.281244e+274
Step-by-step explanation:
I have NO IDEA if that helps,... BUT I hope it does,... Chow,...!
Answer:
water has a specific heat capacity of 4180 j/kg degree cellos
Your numbers are 11 and 32
We know that:
a + b = 44
and
a = 3b
If we substitute “3b” in for a in the first equation, we get a numerical value for b
3b + b = 44
4b = 44
b = 11
Then we substitute the numerical value of b to solve for a:
a = 3b
a = 3(11) = 33
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
The answer is 15 units is the answer boom
Step-by-step explanation: