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disa [49]
3 years ago
8

SOLVE

Mathematics
2 answers:
kramer3 years ago
7 0
A. All real numbers

Explanation:
Using distributive property, distribute the 2 to the (x + 1).
This gives us
2x+2 = 2x+2
Since these equations are equal on both sides, they will be equal no matter what number you use as x.

Hope this helps! Please mark brainliest if you can :)
gavmur [86]3 years ago
5 0

Answer:

I think it's D1 ,

Step-by-step explanation:

2(1+1) = 4

2×1+2=4

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three people share half a pizza evenly. what fractional part of the orgininal pizza does each one get
frozen [14]

Answer:

they each get 1.13

Step-by-step explanation:

cause they do

6 0
3 years ago
Repost: Каков объем этой прямоугольной призмы?
torisob [31]

So first of all we should know that the <u>rectangular prism is a cuboid.</u>

\\  \\

<h3>Given :-</h3>
  • heigth = 9 in.
  • Length = 5 in.
  • Width = 4 in.

\\

<h3>To find:-</h3>
  • Volume of cuboid.

\\

<h3>Solution:-</h3>

We know:-

\bigstar \boxed{ \rm volume \: of \: cuboid = length \times width \times height}

\\  \\

So:-

\dashrightarrow \sf volume \: of \: cuboid = length \times width \times height \\

\\  \\

\dashrightarrow \sf volume \: of \: cuboid = 9 \times 5 \times 4 \\

\\  \\

\dashrightarrow \sf volume \: of \: cuboid = 45 \times 4 \\

\\  \\

\dashrightarrow \bf volume \: of \: cuboid = 180 {in}^{3}  \\

Therefore option C is correct .

\\  \\

<h3>know more:-</h3>

\\  \\

\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{CSA_{(cylinder)} = 2\pi \: rh}\\ \\ \bigstar \: \bf{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bigstar \: \bf{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bigstar \: \bf{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bigstar \: \bf{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bigstar \: \bf{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bigstar \: \bf{Volume_{(cube)} = {(side)}^{3} }\\ \\ \bigstar \: \bf{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bigstar \: \bf{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\ \bigstar \: \bf{Volume_{(cuboid)} = lbh}\\ \\ \bigstar \: \bf{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bigstar \: \bf{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

6 0
3 years ago
If an aerosol can contained 350mL of CFC gas at a pressure of 5.1 atm , what volume would this gas occupy at 1.0atm?
4vir4ik [10]
For this case we have the following relationship:
 P1V1 = P2V2
 Clearing volume 2 we have:
 V2 = (P1 / P2) * (V1)
 Substituting values we have:
 V2 = (5.1 / 1.0) * (350)
 V2 = 1785 mL
 Answer:
 
this gas would occupy 1785 mL at 1.0atm
8 0
3 years ago
Read 2 more answers
Perform the indicated operation. Simplify the result in factored form.
vfiekz [6]

Answer:

\frac{a+1}{(a-2)(a-1)(a-1)}=

Step-by-step explanation:

1. Approach

The easiest method to solve this problem is to factor the expression. In order to subtract (or add) two fractions, both fractions have to have common denominators. When the fractions are factored one can easily see the least common denominator. Convert both fractions to the least common denominator by multiplying the numerator (number over the fraction bar) and denominator (number under the fraction bar) by the value such that both fractions have the same denominator. Finally, one can subtract the numerators of the two fractions.

2. Factoring and Least common denominator

\frac{3}{a^2-3a+2}-\frac{2}{a^2-1}=

Factor the expression, rewrite the quadratic polynomials as the product of two linear polynomials,

\frac{3}{a^2-3a+2}-\frac{2}{a^2-1}=

\frac{3}{(a-2)(a-1)}-\frac{2}{(a-1)(a+1)}=

The least common denominator is: ((a-2)(a-1)(a-1))

Convert both fractions to the least common denominator, multiply both the numerator and denominator by the same value to do so,

\frac{3}{(a-2)(a-1)}-\frac{2}{(a-1)(a+1)}=

\frac{3}{(a-2)(a-1)}*\frac{a-1}{a-1}-\frac{2}{(a-1)(a+1)}*\frac{a-2}{a-2}=

Simplify,

\frac{3}{(a-2)(a-1)}*\frac{a-1}{a-1}-\frac{2}{(a-1)(a+1)}*\frac{a-2}{a-2}=

\frac{3(a-1)}{(a-2)(a-1)(a-1)}-\frac{2(a-2)}{(a-1)(a+1)(a-2)}=

3. Solving the expression

\frac{3(a-1)}{(a-2)(a-1)(a-1)}-\frac{2(a-2)}{(a-1)(a+1)(a-2)}=

Distribute, multiply every term inside the parenthesis by the term outside of it,

\frac{3(a-1)}{(a-2)(a-1)(a-1)}-\frac{2(a-2)}{(a-1)(a+1)(a-2)}=

\frac{3a-3}{(a-2)(a-1)(a-1)}-\frac{2a-4}{(a-1)(a+1)(a-2)}=

Simplify further,

\frac{3a-3}{(a-2)(a-1)(a-1)}-\frac{2a-4}{(a-1)(a+1)(a-2)}=

\frac{3a-3-(2a-4)}{(a-2)(a-1)(a-1)}=

\frac{3a-3-2a+4}{(a-2)(a-1)(a-1)}=

Combine like terms,

\frac{3a-3-2a+4}{(a-2)(a-1)(a-1)}=

\frac{a+1}{(a-2)(a-1)(a-1)}=

4 0
3 years ago
Find the degree of 2b^9c^5
Tems11 [23]

\large \mathfrak{Solution : }

Degree of a polynomial is the highest exponential power in the expression.

i.e 9 here

so, degree of the given expression is 9

6 0
3 years ago
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