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3 years ago

(2x-3)^2=9 factorise

Mathematics

2 answers:

vlabodo [156]3 years ago

8 0

Answer:

Step-by-step explanation:

(2x-3)^2=9

(2x-3)^2=3^ 2

2x - 3 = 3

2x = 3 + 3

2x = 6

x = 6/2

x = 3

irina1246 [14]3 years ago

3 0

Answer:

$x(4x-12)=0$

Step-by-step explanation:

$(2x-3)^2=9\\(2x-3)(2x-3)=9\\4x^2-12x+9=9\\4x^2-12x=0\\x(4x-12)=0$

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Toy cars cost $2. If Anna bought 4 toy cars and 5 toy airplanes and spent $38, how

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Answer: A toy airplane costs $6

Step-by-step explanation: Because 4 toy cars cost $8 , then there are $30 for 5 toy planes. One toy plane cost 30/5 = $6

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3 years ago

Last year, Kaitlin opened an investment account with $8600. At the end of the year, the amount in the account had decreased by 2

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Given that last year Kaitlin opened an investment account with $ 8,600, and at the end of the year, the amount in the account had decreased by 28%, to determine the year-end amount in terms of the original amount both in whole numbers and in decimals, the following calculation must be performed:

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3 years ago

There are 7 people at a party. Each person must shake hands with all the other people at the party once. How many handshakes doe

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3 0

4 years ago

Read 2 more answers

What decimal is equivalent to 13/10

LUCKY_DIMON [66]

Answer:

1.30

Step-by-step explanation:

because it's 13 / 10 it means that there is a whole number , 13 - 10 equals 3 oh, so you divide 3 from 100

4 0

3 years ago

Find the fourth point of a parallelogram given the first three (more than one correct answer is possible): (0,6), (5, -1) and (3

inysia [295]

Answer:

The fourth point of the parallelogram is one point among (-2,2), (2,10) and (8,-12).

Step-by-step explanation:

Given information: The first three vertices of parallelogram are (0,6), (5, -1) and (3,-5).

Let fourth point of the parallelogram is (a,b).

Diagonals of a parallelogram bisect each other. It means midpoint of both diagonals are same.

Midpoint formula:

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Case 1: If the point (0,6), (5, -1) and (3,-5) are consecutive, then pairs of opposite vertices are (0,6) and (3,-5), (5,-1) and (a,b).

$(\frac{0+3}{2},\frac{6-5}{2})=(\frac{5+a}{2},\frac{-1+b}{2})$

$(\frac{3}{2},\frac{1}{2})=(\frac{5+a}{2},\frac{-1+b}{2})$

On comparing both sides, we get

$\frac{3}{2}=\frac{5+a}{2}$

$3=5+a$

$a=-2$

$\frac{1}{2}=\frac{-1+b}{2}$

$1=-1+b$

$b=2$

It means the fourth point of the parallelogram is (-2,2).

Case 2: If the point (0,6), (5, -1) and (3,-5) are not consecutive, then pairs of opposite vertices are (0,6) and (5,-1), (3,-5) and (a,b).

$(\frac{0+5}{2},\frac{6-1}{2})=(\frac{3+a}{2},\frac{-5+b}{2})$

$(\frac{5}{2},\frac{5}{2})=(\frac{3+a}{2},\frac{-5+b}{2})$

On comparing both sides, we get

$\frac{5}{2}=\frac{3+a}{2}$

$5=3+a$

$a=2$

$\frac{5}{2}=\frac{-5+b}{2}$

$5=-5+b$

$b=10$

It means the fourth point of the parallelogram is (2,10).

Case 3: If the point (0,6), (5, -1) and (3,-5) are not consecutive, then pairs of opposite vertices are (5,-1) and (3,-5), (0,6) and (a,b).

$(\frac{5+3}{2},\frac{-1-5}{2})=(\frac{0+a}{2},\frac{6+b}{2})$

$(\frac{8}{2},\frac{-6}{2})=(\frac{a}{2},\frac{6+b}{2})$

On comparing both sides, we get

$\frac{8}{2}=\frac{a}{2}$

$8=a$

$\frac{-6}{2}=\frac{6+b}{2}$

$-6=6+b$

$b=-12$

It means the fourth point of the parallelogram is (8,-12).

5 0

4 years ago