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3 years ago

Difference between 6 and -11

Mathematics

2 answers:

sdas [7]3 years ago

6 0

6 -(-11)
- x - =+(negative x negative =positive
6+11=17

zheka24 [161]3 years ago

3 0

The difference between 6 and -11 is 17
because 6 - (-11) = 17
hope it helps
can l please get brainliest answer?

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The slope of _____ lines to 0.

Sedbober [7]

Answer:

A horizontal line has slope zero since it does not rise vertically (i.e. y1 − y2 = 0), while a vertical line has undefined slope since it does not run horizontally (i.e. x1 − x2 = 0). because division by zero is an undefined operation

Step-by-step explanation:

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3 years ago

a trinalge has two sides of lengths 4 and 7. what value could the length of the third side be? check all that apply A.9 B.11 C.1

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3 years ago

Evaluate 5 - 3(-2) + 1-3|

marishachu [46]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the two inequalities that define the region on the grid that is not shaded

hoa [83]

Answer:

y 》 2

y > -x + 3

Step-by-step explanation:

Equation of the bold line:

m = (-3/3) = -1

y = -x + 3

Shaded region is below y=2 (dotted)

So, it's defined by y < 2

Also, it's below the bold line

y 《 - x + 3

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3 0

3 years ago

A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib

Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 502, \sigma = 115$

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{590 - 502}{115}$

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{400 - 502}{115}$

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

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6 0

2 years ago