They’re all -4 ,, what exactly are you asking ?
Point Form:
(2, 4), (1, 1)
Equation Form:
x = 2, y = 4
x = 1, y = 1
Answer:
Given a triangle ABC, Pythagoras' Theorem shows that:

Thus,

The distance formula, gives an equivalent expression based on two points at the end of the hypotenuse for a triangle.


Therefore when given the hypotenuse with endpoints at

We know that the third point of the right triangle will be at

and that the two side lengths will be defined by the absolute values of:


Answer:
Step-by-step explanation:
That exterior angle of 111 is equal to the sum of the triangle's remote interior angles. We add the 37 + 35 to get a total angle measure of 72. That means that the base angle on the right is 111 - 72 = 39. That 39 degree angle is vertical to x; that means that x = 39 as well.
Step-by-step explanation:
4.
⇒ 
⇒ 
⇒ 
⇒ 
5.
⇒ 
⇒ 
As we know the radius and slant height, we can use Pythagoras' Theorem to find the perpendicular height.
⇒ 
⇒ 
⇒ 
⇒ 
Now substitute this into the volume formula.
⇒ 
⇒ 
⇒ 
6.
⇒ 
⇒ 
⇒ 
7.
⇒ 
⇒ 
⇒ 