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aalyn [17]
3 years ago
5

PLEASE ANSWER PART 2

Mathematics
1 answer:
labwork [276]3 years ago
7 0

Answer:

it is 360

Step-by-step explanation:

all you do is subtact the first number by the second number

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Cody made deposits of $45, $18, and $27 into his checking account. He then wrote checks for $21 and $93. Write an expression to
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<span>C = 45 + 18 + 27 - 21 - 93 C = -24 Let's use the variable C to represent the change in the balance in Cody's checking account. The easiest way to make the expression is to simply apply the additions and subtractions directly. So let's start with C C "Cody made deposits of $45, $18, and $27 into his checking account." C = 45 + 18 + 27 "He then wrote checks for $21 and $93." C = 45 + 18 + 27 - 21 - 93 So the expression to represent the change to Cody's checking account is C = 45 + 18 + 27 - 21 - 93 Now to simplify it. All you need to do is combine terms together. How far you go is up to you. So let's do it. C = 45 + 18 + 27 - 21 - 93 I'll add together all the deposits. C = (45 + 18 + 27) - 21 - 93 C = 90 - 21 - 93 And I'll combine the checks. C = 90 - 114 So now you can tell at a glance that Cody deposited $90 and wrote checks for $114. But we can make it simpler and combine those as well. So C = -24 And this tells you that Cody's checking account balance is now $24 lower than it was before he started making deposits and writing checks.</span>
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Hope This Helps You!
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7 0
2 years ago
Read 2 more answers
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
3 years ago
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