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vlabodo [156]
3 years ago
11

If 5(p+ 3) = 18 + 2р,

Mathematics
2 answers:
KatRina [158]3 years ago
6 0

Answer:

p=1

Step-by-step explanation:

20=20

hope it helps please mark brainliest

marusya05 [52]3 years ago
6 0

Answer:

p = 1

Step-by-step explanation:

5(p+3)=18+2p

5p+15=18+2p

5p-2p=18-15

3p = 3

p = 3/3

p = 1

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Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1
belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

            F(x) = \int\limits^a_b {f(x)} \, dx

By using integration formula

\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

 \int\limits^6_^-6} (x^{5}  + 8 x^{4}  + 2 x^{2}  + 5 x + 15) )dx

<em>On integration , we get</em>

=   (\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}

F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)

= (\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))

After simplification and cancellation we get

 =  \frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6

on calculation , we get

= \frac{124,416}{5} + \frac{864}{3} + 180

On L.C.M  15

= \frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0
3 years ago
Simplify<br> (X+4)+(2x+3)
vfiekz [6]

Answer:

3x + 7

Step-by-step explanation:

<u>Step 1:  Distribute the plus</u>

(x + 4) + (2x + 3)

x + 4 + 2x + 3

<u>Step 2:  Combine like terms</u>

x <u>+ 4</u> + 2x <u>+ 3</u>

<em>3x + 7</em>

<em />

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aleksklad [387]

Answer:

See the explanation below

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<h3>What is the Lateral Surface Area and Surface Area of a Square Pyramid?</h3>

Surface area = a² + 2al, where a is the base edge and l is the slant height.

Lateral Surface Area =  2al.

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Surface area = 451 cm²

Lateral Surface Area =  2al = 2(11)(15)

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Learn more about square pyramid on:

brainly.com/question/3688277

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Savatey [412]

Answer:

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