Kyle bought some $12 shirts. Sally bought some $15 shirts. They each spent less than $200, but they both spent the same amount.

Equation with angles can someone please answer helpppp

Elden [556K]

Answer:

$x = 18°\\\angle A = 73°$

Step-by-step explanation:

By interior angle property on one side of the transversal.

$\angle A+ \angle B = 180°\\6x - 35° + 3x + 53° = 180°\\9x + 18° = 180°\\9x = 180° - 18°\\9x = 162°\\x = \frac{162°}{9}\\ \huge \red {\boxed {x = 18°}} \\\therefore \angle A = 6x - 35°\\\therefore \angle A = 6\times 18°- 35°\\\therefore \angle A = 108°- 35°\\ \huge \purple {\boxed{\therefore \angle A = 73°}} \\$

3 0

3 years ago

I would just love to thank everybody on this app for being so freaking helpful most of you guys dont even know how much of a ble

kipiarov [429]

aww this is soo sweet!!

and yes I wouldn't be able to do it without u all loll

7 0

3 years ago

Read 2 more answers

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

2 years ago

What is the answer please help!!!!!

insens350 [35]

What is the question please help!

6 0

3 years ago

Find the surface area of prism

SCORPION-xisa [38]

Answer:

hope it helps mark me brill

Step-by-step explanation:

The general formula for the total surface area of a right prism is T. S. A. =ph+2B where p represents the perimeter of the base, h the height of the prism and B the area of the base.

4 0

3 years ago