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e-lub [12.9K]
3 years ago
15

What is 0.624 an expanded form

Mathematics
1 answer:
sveta [45]3 years ago
4 0

Answer: 0 + 0.6  + 0.02  + 0.004

A Number in expanded form is written like a sentence.

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Q =3x2+5x-2 R = 2 – x2 S = 2x + 5 Find Q – [R + S] Show all of the steps.
matrenka [14]

Q=3x^2+5x-2\\R=2-x^2\\S=2x+5\\\\Q-[R+S]=(3x^2+5x-2)-[(2-x^2)+(2x+5)]\\\\=(3x^2+5x-2)-(2-x^2+2x+5)\\\\=(3x^2+5x-2)-[-x^2+2x+(2+5)]\\\\=(3x^2+5x-2)-(-x^2+2x+7)\\\\=3x^2+5x-2-(-x^2)-2x-7\\\\=3x^2+5x-2+x^2-2x-7\\\\=(3x^2+x^2)+(5x-2x)+(-2-7)\\\\=\boxed{4x^2+3x-9}

5 0
3 years ago
What is the measure of YB
Ivenika [448]

Answer:

what do y and b stand for

Step-by-step explanation:

please elaborate

5 0
3 years ago
Three times a number x is at least -18
Ksivusya [100]
3x is greater than or equal to -18. You would divide each side by 3 to get x alone. Then You will get what x stands for. (x= -6)
4 0
3 years ago
Brainlist answer!!Can I get some help with this, please!!
Gemiola [76]
A) The question would be "Does cell phone use time correlate to brain cancer?". The population is all cell phone users. The sample is the 469 people with brain cancer, and the 422 healthy people. 

B) This sample size may not portray the entire population of users because the positive results may have been fabricated by factors other than cell phone use. You would have to figure out the population size and determine the correct sample size. 

C) This study may not portray cell phone use correlation over a large population efficiently because of the sample size and the predetermined conclusion that cell phone use causes cancer. 
4 0
3 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:10 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acce
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Answer: If we define 2:00pm as our 0 in time; then:

at t= 0. the velocity is 30 mi/h.

then at t = 10m (or 1/6 hours) the velocity is 50mi/h

Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:

a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/h^{2}

Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)

So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/h^{2}

5 0
3 years ago
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