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3 years ago

Given m(x) = (4 - x)2 + 15 + 2, what is the value of m(3)?

Mathematics

2 answers:

Aneli [31]3 years ago

5 0

Answer:

m(3) = 19

Step-by-step explanation:

m(3) = (4 - 3)2 + 15 + 2

m(3) = 2 + 15 + 2

m(3) = 19

hopefully this makes sense

alexgriva [62]3 years ago

3 0

Answer: 19

Step-by-step explanation:

So, for this problem, you want to find the value of x. When you take a look at m(3), there is a 3 in the place of x, which means the x = 3. Then when you plug 3 into the equation, you get:

(4-3)2 + 15 + 2=

1(2) + 15 +2 =

2 + 15 + 2=

17 + 2=

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Suppose that the mean and s.d of the tuition fee paid by bs mathematics students in umt is 150and 30 in uds, respectively. it is

Serga [27]

From the information give,

A) the probability that the amount paid by him is greater than 105 is ≈ 0.9332

B) the probability that the amount paid by him is not between 120 to 180 ≈ 0.3173

C) the probability that the amount paid by him is between 140 and 160 ≈ 0.2611

D) the probability that the amount paid by him is less than 180 ≈ 0.8413

E) the probability that the amount paid by him is between 140 and 160 given that greater than 120 ≈ 0.3104

F) the probability that the amount paid by him is between 120 and 160orbetween 140 to 180 ≈ 0.6827. See all computations below.

<h3>What is the calculation of for the solutions indicated above?</h3>

Let X be the amount that the student paid;

Note that X ∼ N(μ,σ² ).

Since we have μ = 150, and σ = 30; The1refore

A) P(X>105)=1−P(X≤105)

= 1 - P (Z ≤ (105 -150)/30)

= - P (Z ≤ -1.5)

P(X>105) ≈ 0.9332

B) P(X<120 or X>180)

=P(X<120)+1−P(X≤180)
= P ((Z < (120 - 150)/30) + 1 - P ((Z < (180 - 150)/30)

=P(Z<−1)+1−P(Z≤1)

≈0.158655+0.158655

P(X<120 or X>180) ≈ 0.3173

C) P(140<X<160)

= P(X<160)−P(X≤140)

= P ((Z < (160 - 150)/30) + 1 - P ((Z < (140 - 150)/30)

≈P(Z<0.33333)−P(Z≤−0.33333)

≈0.63056−0.36944

P(140<X<160) ≈ 0.2611

D) P(X<180) = P(Z< (180−150)/30

=P(Z<1)

P(X<180) ≈0.8413

E) P(140<X<160∣X>120)

= (P((140<X<160)∩(X>120))/P(X>120)

= (P((140<X<160))/P(X>120)

= (P Z < (160 -150)/30) - P (Z ≤ (140-150)/30))/ 1- P (Z ≤ (120 - 150)/30)
≈ (P(Z<0.33333)−P(Z≤−0.33333))/ 1 - P(Z ≤ - 1)
≈ (0.63056−0.36944)/0.84134

P(140<X<160∣X>120) ≈ 0.3104

F) P(120<X<160 or 140<X<180)

= P(120<X<180)

= P(X<180)−P(X≤120)

= P ((Z < (180 -150)/30) - P ((Z ≤ (120 -150)/30)

= P(Z<1)−P(Z≤−1)

≈ 0.841345−0.158655

P(120<X<160 or 140<X<180) ≈ 0.6827

Learn more about probability at:

brainly.com/question/24756209
#SPJ1

4 0

2 years ago

In a survey, 24 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped

erica [24]

Answer:

The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 24 - 1 = 23

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.98}{2} = 0.99$ . So we have T = 2.5

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.5\frac{2}{\sqrt{24}} = 1.02$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.

The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.

The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.

7 0

3 years ago

Below is the graph of f ′(x), the derivative of f(x), and has x-intercepts at x = –3, x = 1 and x = 2. There are horizontal tang

mojhsa [17]

Answer:

C. f has a relative maximum at x = 1.

Step-by-step explanation:

A. False. f(x) is concave down when f"(x) is negative. f"(x) is the tangent slope of the graph, f'(x). So f(x) is concave down between x = -1.5 and x = 1.5.

B. False. f(x) is decreasing when f'(x) is negative. So f(x) is decreasing in the intervals x < -3 and 1 < x < 2.

C. True. f(x) has a relative maximum where f'(x) = 0 and changes from + to -.

8 0

3 years ago

Find four fractions between 1/10 and 1/8

Alex17521 [72]

9514 1404 393

Answer:

5/48, 5/46, 5/44, 5/42

Step-by-step explanation:

We can choose unit fractions with denominators between 8 and 10, separated by (10-8)/5 = 0.4 units:

1/8.4 = 5/42

1/8.8 = 5/44

1/9.2 = 5/46

1/9.6 = 5/48

<em>Check</em>

1/8 = 0.125
5/42 ≈ 0.119
5/44 ≈ 0.114
5/46 ≈ 0.109
5/48 ≈ 0.104
1/10 = 0.100

_____

<em>Additional comment</em>

There are an infinite number of such fractions. We are given unit fractions with different denominators, so it works reasonably well to choose denominators between those given. Then the trick is to convert the fraction to a ratio of integers. In this case, multiplying by (5/5) does the trick.

Another approach is to write the fractions with a common denominator, then choose numerators between the ones given. For example, 1/10 = 4/40, and 1/8 = 5/40, so you could write some fractions with numerators between 4 and 5. Possibilities are 4.1/40 = 41/400, 4.3/40 = 43/400, 4.7/40 = 47/400, 4.9/40 = 49/400.

6 0

3 years ago

Please help me. I need help ASAP.

lara [203]

Answer:

a) 72

b) $259.2

Step-by-step explanation:

A- The bus travels 40 miles on 8 gallons of gasoline. The bus is traveling 360 miles in total.

360/40= 9

9*8= 72

B- $3.60 per gallon and 72 gallons in total.

3.60*72=259.2

$259.2

5 0

3 years ago