1. Passage of a sperm through the corona radiata of the oocyte.
2. Penetration of the zona pellucida.
3.Fusion of the plasma cell membranes of the oocyte and sperm. after fusion the sperm head and tail enters the oocyte but plasma membrane of sperm doesn't.
4. Completion of the second meiotic division of the oocyte. this creates female pronucleus and polar body 2.
5. Formation of the male pronucleus (nucleus of sperm enlarges)
6. Breakdown of the pronuclear membranes and restoration of diploid number of chromosomes.
Each of the two threadlike strands into which a chromosome divides longitudinally during cell division. Each contains a double helix of DNA.
The best answer for the above question would be letter b- shape.
Hope I helped if so....pls Mark as brainliest
Answer:
All statements are true about this pathway.
Explanation:
This is the case of noncompetitive inhibition. In this type of inhibition, the inhibitor reduces or lowers the activity of the enzyme and binds equally well to the enzyme.
So as a result of noncompetitive inhibition, the enzyme will be inhibited and less substrate will be transformed into the end product which is D in this case and eventually this pathway will shut down.
Also enzyme 1 has 2 binding sites, 1 for the substrate A and another for the end product D.
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