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kramer
3 years ago
14

Express each of the following numbers as a power of two (2^3)^4 4*4*4*4*4

Mathematics
2 answers:
enot [183]3 years ago
6 0

Answer:

2^12

2^10

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

olya-2409 [2.1K]3 years ago
5 0

Step-by-step explanation:

to the power to the power of - we multiply the powers.

(2³)⁴ = 2¹²

as this is the same as

2³ × 2³ × 2³ × 2³

so, the power is 4×3 = 12

to the power of times to the power of times to the power of ... - we add the powers (if the base is the same).

2²×2²×2²×2²×2² = 2¹⁰

the power is 2+2+2+2+2 or 5×2 = 10

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Solve the quadratic equation by factoring. 9x^2+24x+20=4
const2013 [10]

D. -4/3

Let's solve your equation step-by-step.

9x2+24x+20=4

Step 1: Subtract 4 from both sides.

9x2+24x+20−4=4−4

9x2+24x+16=0

Step 2: Factor left side of equation.

(3x+4)(3x+4)=0

Step 3: Set factors equal to 0.

3x+4=0 or 3x+4=0

x= −4 /3

Hope This helps

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3 years ago
Solve this system by substitution, y = 3 y=-3x + 6 *Remember to write your answer as a coordinate point (x, y). I​
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3 years ago
Leslie paid $12 for 4 books. What is the unit rate of the book purchase?
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Answer: 3 dollars for a book.

Step-by-step explanation:

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Read 2 more answers
For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, ????(????),
Effectus [21]

Answer:

a. Period, T = 12.57 hours. b. Latest time = 294.16 hours, 6 a.m 12 days later

Step-by-step explanation:

For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, d(t), in meters, where t is measured in hours since midnight, is d(t) = 5 + 4.6sin(0.5t). (a) What is the period of the tides in hours? (b) If the boat leaves the bay at midday, what is the latest time it can return before the water becomes too shallow?

a. The period, T of the tides is gotten from ω = 2π/T, where ω is the angular frequency of the wave and T its period. Comparing the sine part of equation of the tides with the general equqtion of a sine wave, Asinωt, thus Asinωt = 4.6sin(0.5t),

so ω = 0.5 rad/s.

Equating this to 2π/T implies

0.5 = 2π/T

therefore, T = 2π/0.5 = 12.566 hours ≈ 12.57 hours

b. The tide becomes too low if it is less than 2.5 m i.e d(t) < 2.5 m. So, equating d(t) as 2.5 in the tidal equation, we have d(t) = 5 + 4.6sin(0.5t).

2.5< 5+ 4.6sin(0.5t)

2.5-5 < 4.6sin(0.5t)

-2.5 < 4.6sin(0.5t)

-2.5/4.6 < sin(0.5t)

-0.543 < sin(0.5t)

sin⁻¹(-0.543)<0.5t

-32.92<0.5t. Since we cannot have negative time, we add 180 to -32.92 to give 147.08

147.08<0.5t

t>147.08/0.5=294.16 hours

So, if t is greater than 294.16 hours, the water will be shallow. That is, below 2.5 m. which is 12 days 6hours 8 min 38 s which is 6 a.m 12 days later

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3 years ago
Amy ran 3/1 miles .Write the distance Amy ran as a decinal?​
Genrish500 [490]

Answer:0.3 miles

Step-by-step explanation:

6 0
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