Ask question

Ask question

All categories

3 years ago

13

If ƒ(x) = 2x² + 3, then which of the following represent ƒ(x + 1)?

1 answer:

Oliga [24]3 years ago

3 0

This is a bit harder. I suggest getting the Domain and Range for the function of x.
If any of these answers have, an infinite domain and (3, infinite) range. That will be your answer.

Your answer is B.

f(x) = 2x²+3 has the same domain and range as x²+3

You might be interested in

-3(x - 2) - (2x - 3) = 5 - (4x - 2)

STatiana [176]

Answer:

x=2

Step-by-step explanation:

-3*(x-2)-(2*x-3)-(5-(4*x-2))=0

((0 - 3 • (x - 2)) - (2x - 3)) - (7 - 4x) = 0

2 - x = 0

-x+2 = 0

Subtract 2 from both sides of the equation :

-x = -2

Multiply both sides of the equation by (-1) : x = 2

4 0

3 years ago

Read 2 more answers

What is the area, in square inches, of a circle with a diameter equal to 16 inches?

Lostsunrise [7]

Answer: 201.06 in²

Step-by-step explanation:

Use the equation πr² to find out the area of a circle.

Since the diameter is 16 the radius is half of that, 8.

π(8)²

Work out that equation and you're done!

7 0

3 years ago

6. A high school graduate works fulltime. She needs to borrow $1,500 to

Rasek [7]

Answer:

I think you would have to multiply 1,500 by 12 and also by 18 to figure it out.

Step-by-step explanation:

" "

4 0

3 years ago

Vinvika [58]

A<b+c so if b=15 and c=40 then
a<15+40
a<45

so a cant possibly be d. 50ft

6 0

3 years ago

Two of the exterior angles of a triangle are $158^\circ$ and $99^\circ.$ Find the third exterior angle, in degrees.

Lisa [10]

Answer:

The third exterior angle is $103^o$

Step-by-step explanation:

Given

$\theta = 158^o$

$\alpha = 99^o$

Required

The third exterior angle $(\beta)$

The exterior angles of a triangle add up to 360 degrees.

So:

$\theta + \alpha + \beta = 360^o$

Make $\beta$ the subject

$\beta = 360^o - (\theta + \alpha)$

Substitute known values

$\beta = 360^o - (158^o + 99^o)$

$\beta = 103^o$

4 0

3 years ago