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liubo4ka [24]
2 years ago
15

PLEASE HELP !!!!!

Mathematics
1 answer:
patriot [66]2 years ago
3 0
P=$1000
Time =3 yrs
Rate =10%
So from the formula of interest =(p*t*r)/100
(1000*3*10)/100
=300
Therefore 300+1000=1300
After 3 years
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Solve for x. Round to the nearest hundredth.
zlopas [31]

<u>Given </u>that the length of the hypotenuse is 8 and the angle is 42°

The length of the one leg of the triangle is x.

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

Substituting the values, we get;

sin \ 42^{\circ}=\frac{x}{8}

Multiplying both sides of the equation by 8, we get;

sin \ 42^{\circ}\times8=x

Simplifying, we get;

0.669 \times 8=x

      5.352\approx x

Therefore, the value of x is 5.35(app.)

Hence, Option A is the correct answer.

8 0
3 years ago
Norma has 9 pies to divide among 4 friends.How many pies will each friend receive if all of the pies must be used and can be div
Romashka [77]

Answer:

2.25

Step-by-step explanation:

9 divided by 4 is 2.25 hope this helped!

8 0
2 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
Digital music distribution provides an opportunity for everyone to get their music heard. In order to get on a service like iTun
Fiesta28 [93]

Based on the charge to the artist and the amount the streaming services pay, the following are true:

  1. -50.
  2. 5.
  3. y = 5x - 50
  4. .
  5. 10,000 streams.
  6. 190,010,000 streams

<h3>What model can be derived for the streaming data?</h3>

The y-intercept would be the amount that the artist has before they start making any money. In this case that amount is -$50 because they will owe the distributor.

The slope is the change per unit which is $5.00 here.

The formula is therefore:

y = mx + b

y = Slope × x + b

y = 5 × x + (-50)

y = 5x - 50

The number of streams to pay off the distributor is when the profit is $0:

0 = 5x - 50

50 = 5x

x = 10 units

Number of streams:

= 10 units x 1,000

= 10,000 streams

To make a profit of $950,000, the units are:

950,000 = 5x - 50

5x = 950,000 + 50

x = (950,000 + 50) / 5

= 190,010 units

Number of streams is:

= 190,010 x 1,000

= 190,010,000 streams

Find out more on linear equations at brainly.com/question/1884491.

#SPJ1

3 0
1 year ago
Find the sum 5/14 + 4/5
AnnyKZ [126]

Answer:

81/70

Step-by-step explanation:

5/14+4/5=25/70+56/70=81/70

3 0
3 years ago
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