Answer:
(7/8 - 4/5)^2 = 9/
1600
= 0.005625
Step-by-step explanation:
Subtract: 7/
8
- 4/
5
= 7 · 5/
8 · 5
- 4 · 8/
5 · 8
= 35/
40
- 32/
40
= 35 - 32/
40
= 3/
40
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(8, 5) = 40. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 8 × 5 = 40. In the next intermediate step, the fraction result cannot be further simplified by canceling.
In words - seven eighths minus four-fifths = three fortieths.
Exponentiation: the result of step No. 1 ^ 2 = 3/
40
^ 2 = 32/
402
= 9/
1600
In words - three-fortieths squared = nine one-thousand six-hundredths.
First off, let's convert the decimal to a fraction, notice, we have two decimals, so we'll use in the denominator, a 1 with two zeros then, two decimals, two zeros, thus
now, we know then the ratio dimensions for the new photograph,
![\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\ -------------------------------\\\\ \cfrac{7}{4}\implies \cfrac{4+3}{4}\implies \cfrac{4}{4}+\cfrac{3}{4}\implies 1+\boxed{\cfrac{3}{4}}\impliedby \textit{perimeter is }\frac{3}{4}\textit{ larger} \\\\\\ \stackrel{areas'~ratio}{\cfrac{s^2}{s^2}}\implies \cfrac{3^2}{4^2}\implies \cfrac{9}{16}\impliedby \textit{area is }\frac{9}{16}\textit{ larger than original}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%5Cqquad%20%5Ccfrac%7Bs%7D%7Bs%7D%3D%5Ccfrac%7B%5Csqrt%7Bs%5E2%7D%7D%7B%5Csqrt%7Bs%5E2%7D%7D%3D%5Ccfrac%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ccfrac%7B7%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B4%2B3%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B4%7D%7B4%7D%2B%5Ccfrac%7B3%7D%7B4%7D%5Cimplies%201%2B%5Cboxed%7B%5Ccfrac%7B3%7D%7B4%7D%7D%5Cimpliedby%20%5Ctextit%7Bperimeter%20is%20%7D%5Cfrac%7B3%7D%7B4%7D%5Ctextit%7B%20larger%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cstackrel%7Bareas%27~ratio%7D%7B%5Ccfrac%7Bs%5E2%7D%7Bs%5E2%7D%7D%5Cimplies%20%5Ccfrac%7B3%5E2%7D%7B4%5E2%7D%5Cimplies%20%5Ccfrac%7B9%7D%7B16%7D%5Cimpliedby%20%5Ctextit%7Barea%20is%20%7D%5Cfrac%7B9%7D%7B16%7D%5Ctextit%7B%20larger%20than%20original%7D)
Answer:
Answer will 19/4 hope it helps
1) <span>Pairs A(2, 5), B(6, 5), and C(6, 1)
point D
Dx=Cx-(Bx-Ax)=(6-(6-2))=2
Dy=Cy=1
</span>the coordinates of vertex D is (2,1)
2) Pairs <span>A(2, 3), B(7, 3), and C(7, -2)
</span>point D
Dx=Cx-(Bx-Ax)=(7-(7-2))=2
Dy=Cy=-2
the coordinates of vertex D is (2,-2)
3) Pairs <span>A(-5, -1), B(1, -1), and C(1, -5)
</span>point D
Dx=Cx-(Bx-Ax)=(1-(1+5))=-5
Dy=Cy=-5
the coordinates of vertex D is (-5,-5)
4) Pairs <span>A(-1, 4), B(7, 4), and C(7, -1)
</span>point D
Dx=Cx-(Bx-Ax)=(7-(7+1))=-1
Dy=Cy=-1
the coordinates of vertex D is (-1,-1)
