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Firdavs [7]
3 years ago
12

Keshawn left his house at time zero and drove for 4 minutes to the store, at a speed of 1 blocks per minute. Then he stopped and

went into the store for 2 minutes. From there, he drove in the same direction at a speed of 4 blocks per minute until he got to the bank, which is 16 blocks away from the store. He stopped at the bank for 6 minutes. Then he drove home at a speed of 10 blocks every minute. Make a graph of showing the number of blocks away from home that Keshawn is xx minutes after he leaves his house, until he gets back home.
Mathematics
1 answer:
Sphinxa [80]3 years ago
6 0

Start from (19,8), take 2 minutes to travel 8 blocks back, end at (21,0).

Step-by-step explanation:

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A flagpole is at the top of a building. 300 feet from the base of the building, the angle of elevation of the top of the pole is
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Answer: We can use tangent here to find the length of the flagpole

First, find the length of the building + the flag pole

tan 32 = x/300

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7 0
3 years ago
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jonny [76]

4 < 4(6y - 12) - 2y       |use distributive property

4 < (4)(6y) + (4)(-12) - 2y

4 < 24y - 48 - 2y       |add 48 to both sides

52 < 26y      |divide both sides by 26

2 < y → y > 2

---------------------------------------------------------

4x + 3 < 3x + 6      |subtract 3 from both sides

4x < 3x + 3       |subtract 3x from both sides

x < 3

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-5r + 6 ≤ -5(r + 2)        |use distributive property

-5r + 6 ≤ (-5)(r) + (-5)(2)

-5r + 6 ≤ -5r - 10         |add 5r to both sides

6 ≤ -10     FALSE

No solution

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-2(6 + s) ≥ -15 - 2s        |use distributive property

(-2)(6) + (-2)(s) ≥ -15 - 2s

-12 - 2s ≥ -15 - 2s        |add 2s to both sides

-12 ≥ -15     TRUE

All real numbers

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3s + 6 ≤ -5(s + 2)        |use distributive property

3s + 6 ≤ (-5)(s) + (-5)(2)

3s + 6 ≤ -5s - 10         |subtract 6 from both sides

3s ≤ -5s - 16        |add 5s to both sides

8s ≤ -16         |divide both sides by 8

s ≤ -2

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4/3 s - 3 ?

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3 years ago
A rectangular swimming pool that is 10 ft wide by 16 ft long is surrounded by a cement sidewalk of uniform width. If the area of
Alchen [17]
We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
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Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
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x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.

The value of x is <span>5 feet. </span>

5 0
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