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Firdavs [7]
3 years ago
12

Keshawn left his house at time zero and drove for 4 minutes to the store, at a speed of 1 blocks per minute. Then he stopped and

went into the store for 2 minutes. From there, he drove in the same direction at a speed of 4 blocks per minute until he got to the bank, which is 16 blocks away from the store. He stopped at the bank for 6 minutes. Then he drove home at a speed of 10 blocks every minute. Make a graph of showing the number of blocks away from home that Keshawn is xx minutes after he leaves his house, until he gets back home.
Mathematics
1 answer:
Sphinxa [80]3 years ago
6 0

Start from (19,8), take 2 minutes to travel 8 blocks back, end at (21,0).

Step-by-step explanation:

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12=4-4x<br>PLEASE HELPPP​
Alex_Xolod [135]

Answer:

-2

Step-by-step explanation:

4x=4-12

4x=-8

X=-2

And answer is - 2

4 0
3 years ago
Solve the following system by graphing. If there​ isn't a unique solution to the​ system, state the reason. y=-2x y=2x+4
natka813 [3]

Answer:

We have the system of equations:

y = -2*x

y = 2*x + 4.

To solve it by graphing, you need to graph both lines and see in which point the lines intersect each other.

You can see it in the image below. (blue is y = 2*x + 4, and green is y = -2*x)

We also can calculate the solution with math, let's do that:

y = -2*x

y = 2*x + 4.

We can replace the first equation in the second one, to get:

-2*x = 2*x + 4

Now let's solve this for x

-2*x -2*x = 4

-4*x = 4

x = 4/-4 = -1

Evaluating this in one of the equations we get:

y = -2*-1 = 2

Then the solution is the point (-1, 2), exactly what we can see in the graph.

3 0
3 years ago
If 4 classrooms can seat 188 students how many classrooms would be needed to seat 517 students?
Alenkinab [10]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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Solve algebraically the simultaneous equations<br><br> X^2 + Y^2 =25<br> Y-2X = 5
Georgia [21]

Answer:

Therefore the solutions are

x=0\\and\\ y =5\\\\Or\\\\x=-4\\and\\y=-3

Step-by-step explanation:

Given:

x^{2} + y^{2} =25 .........( 1 )

y-2x = 5\\y=2x+5     ................( 2 )

To Find:

x = ?

y = ?

Solution:

Substituting ' y ' in Equation  1 we get

x^{2}+(2x+5)^{2} =25

Using identity (A+B)²=A²+2AB+B² we get

x^{2}+4x^{2}+20x+25=25\\\\5x^{2}+20x=0\\5x(x+4)=0\\5x=0\ or\ x+4=0\\x=0\ or\ x= -4

Now Substitute x =0 in equation 2 we get

y=2\times 0+5=5

Or

Now Substitute x =-4 in equation 2 we get

y=2\times -4+5=-3

Therefore the solutions are

x=0\\and\\ y =5\\\\Or\\\\x=-4\\and\\y=-3

4 0
4 years ago
My math question is 1/6+2/3 in simple form
Ad libitum [116K]
1/6 + 2/3=
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4 years ago
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