Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
In order to solve, set up a proportion: 22/126=x/100. Cross multiply: 2200=126x. Divide by 126 on both sides: 17.46%=x
15%
Step-by-step explanation:
Absent= 6
Total student = 40
Answer:
The answer would be z/6 + 5 - 8.
Step-by-step explanation:
Quotient means the answer to a division problem, so we know that z and 6 must be divided. Then it tells us to add 5 to the quotient and then subtract 8 from the total. Because of PEMDAS no parentheses are needed.
Okay. So, based off of that, if you divide 1 1/2 (3/2) by 3/4, 3/2 * 4/3 is 12/6 or 2. 1/2 cups of raspberries is needed for each fourth of the cake. 1/2 * 4 = 2. Lin will need 2 cups of raspberries for the whole cake.
