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shepuryov [24]
3 years ago
11

(Click the picture to see math question) please help I’ll mark brainliest

Mathematics
1 answer:
FromTheMoon [43]3 years ago
3 0

Answer:

g(x) = f(x + 2)

Step-by-step explanation:

The x value has been translated by 2

<em>Feel free to mark it as brainliest :D</em>

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How many<br>weeks are there in 81 days​
natima [27]

Answer: At least 8

Reason: A week has 7 days in it, so when you divide 81 by 7, you get 7.5, so when you round it, you get the number 8

<u><em>If you have any questions, corrections, or problems, let me know. I hope this helped</em></u>

4 0
2 years ago
Which of the following equations could be used to solve for the tenth term of the following sequence? 15,13,11,9,… A(10)=15+10(-
coldgirl [10]

Answer:

the first one

Step-by-step explanation:

3 0
2 years ago
You get tired of the sand and head up to the amusement park. You can purchase 20 ride tickets for $14 or you can purchase 30 rid
Helga [31]

Answer:

The one with the better deal would be 30 ride tickets for $22.50 this is because you pay less money for more rides.

Step-by-step explanation:

First you divide 20 by 14. Doing this will give you the cost of a ride per ticket.

20/14 = 1.42

Then you do the same thing to 30 and 22.50.

30/22.50 = 1.30

Last you compare which deal has less money per ride.

1.42 > 1.30

5 0
3 years ago
Write the polynomial in standard form.<br> - 4 + 3x - 522
Tatiana [17]

Answer:

3x-526

Step-by-step explanation:

the 3x would go in the beginning. then you subtract (-4-522)= -526.

4 0
2 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It
Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92

Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0
3 years ago
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